Question

Four pounds of gas occupy 10ft^3. What would be it’s density and specific gravity

Answer 1

Answer:

$\large \boxed{\text{ 0.4 lb/ft}^{3}; 5}$

Step-by-step explanation:

1. Density

$\begin{array}{rcl}\text{Density} & = & \dfrac{\text{Mass}}{\text{Volume}}\\\\& = & \dfrac{\text{4 lb}}{\text{10 ft}^{3}}\\\\& = &\textbf{0.4 lb/ft}^{\mathbf{3}}\\\end{array}\\\text{The density of the gas is \large \boxed{\textbf{ 0.4 lb/ft}^{\mathbf{3}}} }$

2. Specific gravity

Specific gravity (sp gr) is the ratio of the density of the density of a gas to the density of dry air at standard temperature and pressure.

At IUPAC standard temperature and pressure (0 °C and 100 kPa), dry air has a density of 0.080 lb/ft³.

$\begin{array}{rcl}\text{Sp gr}& = & \dfrac{\rho_{\text{gas}}}{\rho_{\text{dry air}}}\\\\& = & \dfrac{\text{0.4 lb/ft}^{3}}{\text{0.080 lb/ft}^{3}}\\\\& = &\mathbf{5}\\\end{array}\\\text{The specific gravity of the gas is \large \boxed{\mathbf{5}} }$