Please help i will give crowns
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For the function to be continuous at any x-value you need the left-hand limit to match the right-hand limit to match the function's value at that x-value.
For example, for the function to be continuous at x=2:
must equal
This must also equal or
.
So start by finding the first limit that has no a's or b's in it and set that equal to 4a-2b-16.
The problem is that this is only one equation and there are two variables, so we need a second equation to set up to be able to solve for a and b.
So, you need to repeat that whole process with the pieces on either side of x=3. We need to have:
That will give you a second equation with a's and b's. Once you have that, you'll have a system which you can solve using substitution or elimination.