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Art [367]
3 years ago
10

Please help ASAP ! The question below

Mathematics
1 answer:
Anuta_ua [19.1K]3 years ago
8 0

Answer:

a x = 14.3 units

Step-by-step explanation:

The Pythagorean theorem is

a^2 +b^2 = c^2  where a and b are the sides and c is the hypotenuse

x^2 + 14^2 = 20^2

x^2 +196 = 400

Subtract 196 from each side

x^2+196-196 = 400-196

x^2 =204

Take the square root of each side

sqrt(x^2) = sqrt(204)

x =14.28285686

To the nearest tenth

x = 14.3 units

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given that sin theta= 1/4, 0 is less than theta but less than pi/2, what is the exact value of cos theta
lapo4ka [179]

Answer:

\cos{\theta} = \frac{\sqrt{15}}{4}

Step-by-step explanation:

For any angle \theta, we have that:

(\sin{\theta})^{2} + (\cos{\theta})^{2} = 1

Quadrant:

0 \leq \theta \leq \frac{\pi}{2} means that \theta is in the first quadrant. This means that both the sine and the cosine have positive values.

Find the cosine:

(\sin{\theta})^{2} + (\cos{\theta})^{2} = 1

(\frac{1}{4})^{2} + (\cos{\theta})^{2} = 1

\frac{1}{16} + (\cos{\theta})^{2} = 1

(\cos{\theta})^{2} = 1 - \frac{1}{16}

(\cos{\theta})^{2} = \frac{16-1}{16}

(\cos{\theta})^{2} = \frac{15}{16}

\cos{\theta} = \pm \sqrt{\frac{15}{16}}

Since the angle is in the first quadrant, the cosine is positive.

\cos{\theta} = \frac{\sqrt{15}}{4}

3 0
3 years ago
Theresa Morgan, a chemist, has a 30% hydrochloric acid solution and a 50% hydrochloric acid solution. How many liters of each sh
Bogdan [553]
Let x represent the number of liters of 50% acid Theresa puts into the mix. The the number of liters of 30% acid will be (420-x). The total amount of acid in the final solution will be ...
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  0.20x + 126 = 189 . . . . . . . . . . . . . . . simplify
  0.20x = 63 . . . . . . . . . . . . . . . . . . . . . subtract 126
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Theresa should mix ...
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X^{2m+n} * x^{n-m} / x^{m+2n}
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Answer:

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Step-by-step explanation:

3 0
3 years ago
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Which number is eqyal to 13​
Ostrovityanka [42]
Answer:
XIII

Hope this helps
6 0
2 years ago
A line has x-intercept of 6 and y-intercept of -4.Find the slope of the line.
Zigmanuir [339]

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3 0
2 years ago
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