Let , side lawn is a.
Area of boundary is :
![A=4\times5\times a\\\\A=20a\ m^2](https://tex.z-dn.net/?f=A%3D4%5Ctimes5%5Ctimes%20a%5C%5C%5C%5CA%3D20a%5C%20m%5E2)
Now, total cost is given by :
![T=20a\times 36.25\\\\90625=725a\\\\a=125\ m](https://tex.z-dn.net/?f=T%3D20a%5Ctimes%2036.25%5C%5C%5C%5C90625%3D725a%5C%5C%5C%5Ca%3D125%5C%20m)
Area left is :
![A'=a^2-20a\\\\A'=125^2-20\times 125\ m^2\\\\A'=13125\ m^2](https://tex.z-dn.net/?f=A%27%3Da%5E2-20a%5C%5C%5C%5CA%27%3D125%5E2-20%5Ctimes%20125%5C%20m%5E2%5C%5C%5C%5CA%27%3D13125%5C%20m%5E2)
Price to empty space with turfs is :
![P=A'\times 20\\\\P=13125\times 20\\\\P=262500](https://tex.z-dn.net/?f=P%3DA%27%5Ctimes%2020%5C%5C%5C%5CP%3D13125%5Ctimes%2020%5C%5C%5C%5CP%3D262500)
Therefore, the cost of covering the empty space with turfs at the rate of Rs 20 per sq. metre is Rs 262500.
Hence, this is the required solution.
Answer:
Option B is the correct choice.
Step-by-step explanation:
The graph is attached below.
We have to find the
intercept meaning the value of the point on
when ![y=0](https://tex.z-dn.net/?f=y%3D0)
So we will put the value of zero
instead of
in our given equation.
So here we have solved it algebraically.
![y=\frac{3}{4}x-3](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B3%7D%7B4%7Dx-3)
Putting ![y=0](https://tex.z-dn.net/?f=y%3D0)
![0=\frac{3}{4}x-3](https://tex.z-dn.net/?f=0%3D%5Cfrac%7B3%7D%7B4%7Dx-3)
![0=\frac{3x-12}{4}](https://tex.z-dn.net/?f=0%3D%5Cfrac%7B3x-12%7D%7B4%7D)
Multiplying
both sides.
![0=3x-12](https://tex.z-dn.net/?f=0%3D3x-12)
Adding
both sides.
![12=3x](https://tex.z-dn.net/?f=12%3D3x)
Dividing with
both sides.
![x=\frac{12}{3}=4](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B12%7D%7B3%7D%3D4)
So the x-intercept of the given equation is
which can be written as
in terms of coordinates.
Option B
is the correct choice.
Answer: 5.14 cu in
Step-by-step explanation:
1/2 (π × d) + d, where d is the diameter of the semi
Perimeter = 1/2 (3.14 x 2) + 2
= 1/2 * 6.28 + 2
= 3.14 + 2
R = sqrt 3 * (V /( pi * h))
V = 62.8
pi = 3.14
h = 15
now we sub
R = sqrt 3 * (62.8 / (3.14 * 15)
R = sqrt 3 * (62.6 / 47.1)
R = sqrt 3 * 1.33
R = sqrt 3.99
R = 1.9 rounds to 2 inches <===
Answer:
663
Step-by-step explanation:
the total number of students can be determined using this equation :
(total ratio of Chinese and Indian students / total ratio of students) x n = 468
total ratio of Chinese and Indian students = 4 + 8 = 12
total ratio of students 4 + 8 + 5 = 17
N = TOTAL NUMBER OF STUDENTS
12/17) x n = 468
multiply both sides of the equation by 17/12
n = 663