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3 years ago

2339.1 in standard form or scientific notation

Chemistry

2 answers:

zhenek [66]3 years ago

6 0

See under both it comes

disa [49]3 years ago

6 0

You move it to three

2.2391 x 10 exponent 3

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The ratio of chlorine to hydrogen chloride in the reaction H2(g) + Cl2 (g) -> 2 HCl(g) is

cupoosta [38]

It is a simple stoichiometry problem. We have been given with balanced equation and 5.00 moles of HCl and have to calculate the moles of H2.

From the balanced equation it is being clear that 2 moles of HCl are produced by 1 mole of H2. so, 1 mole of HCl will be produced by 1/2 moles of H2. So, the mole ratio of H2 and HCl is 1:2 
to calculate the moles of H2 for the given moles of HCl, multiply the moles of HCl by the mole ratio of H2 and HCl. 

5.00 mole HCl x (1 mole H2/ 2 mole HCl) 
= 2.50 mole H2 
so, to produce 5.00 moles of HCl, 2.50 moles of H2 are required.

8 0

3 years ago

What is the chemical name of the compound Ti2O3? Use the list of polyatomic ions and the periodic table to help you answer.

sergey [27]

The compound name of this chemical is Titanium(III) oxide

8 0

3 years ago

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What do all magnets have in common? Select all that apply

Ede4ka [16]

Answer:

Explanation:

all magnets have opposite poles (north and south)

magnetic domains are aligned

moving electrons generate a magnetic filed

movement of electrons creates a magnets field

attracted to iron, nickel and cobalt

5 0

3 years ago

A large pot (10 kg) of beef stew is left out on the kitchen counter to cool. The rate of cooling, in kJ/min, equals 1.955 (T-25)

olga_2 [115]

Answer:

16 minutes

Explanation:

First, we need to calculate the amount of heat needed to cool the beef stew:

Q = mcΔT

Where m is the mass, c is the heat capacity and ΔT is the variation of the temperature.

Q = 10x4x(40 - 90)

Q = -2000 kJ

So, the beef stew needs to lost 2000 kJ to cool.

With the initial temperature at 90ºC, the rate of cooling(r) will be:

r = 1.955x(90 - 25)

r = 127.075 kJ/min

So, to lose 2000 kJ, will be necessary:

t = Q/r

t = 2000/127.075

t = 16 minutes

5 0

3 years ago

In the reaction FeCl2 + 2NaOH ->Fe(OH)2(s) + 2NaCl, if 6 moles of FeCl2 are added to 6 moles of Na0H, how many moles of NaOH

pogonyaev

Answer : The correct option is, (B) 6 mole

Explanation :

Given moles of $FeCl_2$ = 6 moles

Given moles of $NaOH$ = 6 moles

First we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

$FeCl_2+2NaOH\rightarrow Fe(OH)_2+2NaCl$

From the given balanced reaction, we conclude that

As, 1 moles of $FeCl_2$ react with 2 moles of $NaOH$

So, 6 moles of $FeCl_2$ react with $\frac{2}{1}\times 6=12$ moles of $NaOH$

From this we conclude that, $FeCl_2$ is an excess reagent and $NaOH$ is a limiting reagent because the given moles are less than the required moles and it limits the formation of product.

Thus, the number of moles of NaOH used up in the reaction = Required moles of NaOH - Given moles of NaOH

The number of moles of NaOH used up in the reaction = 12 - 6 = 6 moles

Therefore, the number of moles of NaOH used up in the reaction will be, 60 moles

4 0

3 years ago

Read 2 more answers