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umka2103 [35]
4 years ago
15

Which of the following sets of empirical formula, molar mass, and molecular formula is correct?

Chemistry
1 answer:
lutik1710 [3]4 years ago
3 0

Answer:

CH4N, 90g, C3H12N3

Explanation:

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D. TTACGCCAGG. that would be your answer.

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How do I convert/scale a recipe using a t chart
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Obtain the conversion factor by dividing the required yield (from Step 2) by the old yield (from Step 1). That is, conversion factor = (required yield)/(recipe yield) or conversion factor = what you NEED ÷ what you HAVE.

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Jose times how long sugar takes to dissolve in warm water. He conducts four trials of his experiment. What should he conclude fr
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His experiment has very low precision

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3 years ago
In the reaction of silver nitrate with copper metal, metallic silver comes out of solution, and the solution turns blue. This as
aalyn [17]

Answer:

Single displacement reaction.

Explanation:

Hello!!

In this case, since the reaction between silver nitrate and copper metal is:

2AgNO_3(aq)+Cu(s)\rightarrow 2Ag(s)+Cu(NO_3)_2(aq)

As silver was forming silver nitrate, due to the presence of copper, which has the capacity to displace silver out of the salt, we notice the formation of solid silver and a resulting copper (II) nitrate which is blue in aqueous solution.

Therefore, this is a single displacement reaction, because the the lonely copper displaced the silver.

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7 0
3 years ago
A 20.0–milliliter sample of 0.200–molar K2CO3 so­lution is added to 30.0 milliliters of 0.400–mo­lar Ba(NO3)2 solution. Barium c
iragen [17]

Answer:

[Ba^2+] = 0.160 M

Explanation:

First, let's calculate the moles of each reactant with the following expression:

n = M * V

moles of K2CO3 = 0.02 x 0.200 = 0.004 moles

moles of Ba(NO3)2 = 0.03 x 0.400 = 0.012 moles

Now, let's write the equation that it's taking place. If it's neccesary, we will balance that.

Ba(NO3)2 + K2CO3 --> BaCO3 + 2KNO3

As you can see, 0.04 moles of  K2CO3 will react with only 0.004 moles of Ba(NO3) because is the limiting reactant. Therefore, you'll have a remanent of

0.012 - 0.004 = 0.008 moles of Ba(NO3)2

These moles are in total volume of 50 mL (30 + 20 = 50)

So finally, the concentration of Ba in solution will be:

[Ba] = 0.008 / 0.050 = 0.160 M

6 0
3 years ago
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