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3 years ago

Which equation describes the line graphed above? A. -4x-5 B. -1/5x-4 C. -5x-4 C. -4x-1/5

Mathematics

2 answers:

SashulF [63]3 years ago

8 0

Answer: B

Explanation:

The line go down one and turn right 5

So slope = -1/5x

And the y intercept is at -4

So B is the correct answer

BigorU [14]3 years ago

3 0

Answer:

Step-by-step explanation:

The line contins points: (-5, -3) and (5, -5) so the slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{-5-(-3)}{5-(-5)}=\dfrac{-5+3}{5+5}=\dfrac{-2}{10}=-\dfrac15$

and y-intercept is b = -4

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Solve the following equations;- x - 9 /√x + 3 =1

fgiga [73]

Answer:

13 , 6.

Step-by-step explanation:

A equation is given to us and we need to find out the value of x . The given equation to us is ,

$\sf\implies \dfrac{ x -9}{\sqrt{x+3}}= 1$

Cross multiply ,

$\sf\implies x - 9 =\sqrt{ x +3}$

Squaring both sides ,

$\sf\implies (x - 9)^2 = x + 3$

Simplify the whole square ,

$\sf\implies x^2+9^2-2.9.x = x +3 \\$

$\sf\implies x^2+81 - 18x = x -3$

Add 3 and subtract x on both sides ,

$\sf\implies x^2 -18x-x +81-3=0$

Simplify ,

$\sf\implies x^2 -19x +78=0$

Split the middle term of the quadratic equation,

$\sf\implies x^2-13x-6x+78=0$

Take out common ,

$\sf\implies x( x -13)-6(x-13)=0$

Take out ( x -13 ) as common ,

$\sf\implies ( x -13)(x-6)=0$

Equate both factors to 0 ,

$\sf\implies \boxed{\pink{\sf x = 13,6}}$

Hence the value of x is 13 or 6 .

7 0

3 years ago

Can someone help me with this question

Dmitriy789 [7]

Answer:

The horizontal shift is to the left by 2 units and the vertical shift is down 3 units for this function.

I hope I was able to help!

Step-by-step explanation:

7 0

2 years ago

The figure shows a kite inside a rectangle. Which expression represents the area of the shaded region? 2x2 4x2 6x2 8x2

Savatey [412]

The picture in the attached figure

we know that
area of the the shaded region=area of rectangle -area of a kite

area of rectangle=(3x+x)*(x+x)----> 4x*2x---> 8x²

area of a kite=(1/2)*[d1*d2]
where d1 and d2 are the diagonals
d1=4x
d2=2x
so
area of a kite=(1/2)*[4x*2x]----> 4x²

area of the the shaded region=8x²-4x²-----> 4x²

the answer is
4x²