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aleksley [76]
3 years ago
8

14 ft ? 4 yd is <,>,or =

Mathematics
2 answers:
zubka84 [21]3 years ago
8 0
14 feet is larger because 1 yard is 3 feet. so 4*3=12 ft, and 12ft is less than 14 ft
xxTIMURxx [149]3 years ago
8 0
14 feet > 4 yards because a yard is 3 feet and 3*4 is 12 not 14
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I'll give u brianliest if you share the answer and how you got it
Bogdan [553]

Answer:a is 52    b is 65

Step-by-step explanation:

a:Write 65% as 65100.

65100 of 80 = 65100 × 80.

Therefore, the answer is 52. If you are using a calculator, simply enter 65÷100×80 which will give you 52 as the answer.

b: it is 65 because it is the same question but in reverse which still gives you the same answer.

Hope this helps

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3 years ago
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DerKrebs [107]
Quadratic function.
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From a random sample of size 18, a researcher states that (11.1, 15.7) inches is a 90% confidence interval for mu, the mean leng
alexandr402 [8]

Complete Question

From a random sample of size 18, a researcher states that (11.1, 15.7) inches is a 90% confidence interval for mu, the mean length of bass caught in a small lake. A normal distribution was assumed. Using the 90% confidence interval obtain:

a. A point estimate of \mu and its 90% margin of error.

b. A 95% confidence interval for \mu.

Answer:

a

\= x  = 13.4   .   E = 2.3

b

10.7 <  \mu < 16.1

Step-by-step explanation:

From the question we are told that

  The sample size is  n = 18

  The 90% confidence interval is  (11.1, 15.7)

Generally the point estimate of  \mu is mathematically  evaluated  as

       \= x  = \frac{11.1 + 15.7 }{2}

=>    \= x  = 13.4

Generally the margin of error is mathematically evaluated  as

     E = \frac{15.7 - 11.1}{2 }

=> E = 2.3

  From the question we are told the confidence level is  90% , hence the level of significance is    

      \alpha = (100 - 90 ) \%

=>   \alpha = 0.10

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.645

Generally the equation for the lower limit of the confidence interval is  

      \= x  -  Z_{\frac{\alpha }{2} } * \frac{s}{\sqrt{18} } = 11.1

=> 13.4   -  0.3877 s  = 11.1

=>  s = 5.932

  From the question we are told the confidence level is  95% , hence the level of significance is    

      \alpha = (100 - 95 ) \%

=>   \alpha = 0.05

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.96

Generally the margin of error is mathematically represented as  

      E = Z_{\frac{\alpha }{2} } *  \frac{\sigma }{\sqrt{n} }

=>    E =  1.96 *  \frac{5.932}{\sqrt{18} }

=>    E =  2.7      

Generally 95% confidence interval is mathematically represented as  

      \= x -E <  \mu <  \=x  +E

=>    13.4  -  2.7  <  \mu < 13.4  +   2.7

=>    10.7 <  \mu < 16.1

3 0
3 years ago
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Charra [1.4K]

Answer:

Point-slope form:

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3 years ago
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tresset_1 [31]

Answer:

Step-by-step explanation:

Given the Total revenue R(x) = 2x

Cost C(x) = 0.01x²+0.3x+30 where;

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dR/dt = 2dx/dt

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Rate of change of revenue with respect to time is 18dollars/day.

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dC/dt = (0.02x+0.3)dx/dt

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dC/dt = {0.02(30)+0.3}×9

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dC/dt = $8.1

Rate of change of cost with respect to time is 8.1dollars/day

Profit = Revenue - Cost

Profit = 18-8.1

Daily Profit = $9.9

4 0
3 years ago
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