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bogdanovich [222]
3 years ago
15

Which value of the vanable is a solution of the inequality? t<-6 7 6 -6 -7

Mathematics
1 answer:
oksian1 [2.3K]3 years ago
6 0

Answer:

-7

Step-by-step explanation:

-7 is a solution of the inequality t<-6

By the way, for the number -6, you can think about a temperature below zero. When it is freezing 6 degrees below zero (-6) it is pretty cold.

The question is which number(s) can you substitute for t so that the formula (the inequality) is True.

So let's try for each given value and substitute it for t in t<-6

if you substitute 7 for t you get this:

Is 7 smaller then -6 ?

No that is not true because 7 is bigger then -6.

if you substitute 7 for t you get this:

Is 7 smaller then -6 ?

No that is not true because 7 is much bigger then -6.

if you substitute 6 for t you get this:

Is 6 smaller then -6 ?

No that is not true because 6 is much bigger then -6.

if you substitute -6 for t you get this:

Is -6 smaller then -6 ?

No, that is NOT true because -6 is exactly the same as -6 but NOT smaller then -6...

if you substitute-7 for t you get this:

Please think about temperatures below zero again.

Is -7 colder the -6 ? If so, then the statement is true...

Is -7 smaller then -6 ?

Yes that is true!

So -7 is a solution of the inequality t<-6

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On a linear X temperature scale, water freezes at −115.0°X and boils at 325.0°X. On a linear Y temperature scale, water freezes
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Answer:

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Let is determine first the ratio of change in X linear temperature scale to change in Y linear temperature scale:

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r = \frac{325\,^{\circ}X-(-115\,^{\circ}X)}{-25\,^{\circ}Y - (-65.00\,^{\circ}Y)}

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The difference between current temperature in Y linear scale with respect to freezing point is:

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The change in X linear scale is:

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