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2 years ago

Find the value of x and the value of y.

Mathematics

1 answer:

mezya [45]2 years ago

3 0

Answer i pick is A. got to MULTIPLE BY 2 FOR X

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Solve for y z= x+y/5 due in 9 mins

Makovka662 [10]

Answer:

y = 5z - x

Step-by-step explanation:

Given

z = $\frac{x+y}{5}$ ( multiply both sides by 5 to clear the fraction )

5z = x + y ( subtract x from both sides )

5z - x = y

7 0

3 years ago

What is 50(4+6)?<br> πωπ

slava [35]

Step-by-step explanation:

50(4+6)=500

hope it helps you get

3 0

3 years ago

Read 2 more answers

1.) Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth .x squared minus 21 x equals n

Andrew [12]

Part 1
We are given $x^2-21x=-4x$ . This can be rewritten as $x^2-18x=0$ .
Therefore, a=1, b=-18, c=0.
Using the quadratic formula
$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}=\frac{-\left(-18\right)\pm \sqrt{\left(-18\right)^2-4\left(1\right)\left(0\right)}}{2\left(1\right)}$
$x=\frac{18\pm 18}{2}$

The values of x are
$x_1=\frac{18-18}{2}=0$
$x_2=\frac{18+18}{2}=18$

Part 2
Since the values of y change drastically for every equal interval of x, the function cannot be linear. Therefore, the kind of function that best suits the given pairs is a quadratic function.

Part 3.
The first equation is $y=x^2+2$ .
The second equation is $y=3x+20$ .

We have
$x^2+2=3x+20$
$x^2-3x-18=0$
Factoring, we have
$\left(x-6\right)\left(x+3\right)=0$
Equating both factors to zero.
$x_1-6=0\rightarrow x_1=6$
$x_2+3=0\rightarrow x_2=-3$

When the value of x is 6, the value of y is
$y=3\left(6\right)+20=38$

When the value of x is -3, the value of y is
$y=3\left(-3\right)+20=11$

Therefore, the solutions are (6,38) or (-3,11)

7 0

2 years ago

How to solve this one

nalin [4]

Answer:

Step-by-step explanation:

w^3 + 4w^2 + 5w - 12

3 0

2 years ago

Read 2 more answers

What is the classification for this polynomial 2u^2vw^2

Alexxx [7]