Here the given expression is
We need to find the value of y when x =3 . So we substitute the value of x in the given expression.
So when x=3, y=0.4 and that's the required answer.
6x^2+14x+4
First factor out all numerical factors (=2 in this case)
2(3x^2+7x+2)
look for m,n such that m*n=3*2, m+n=7 => m=6, n=1
2(3x^2+6x + 1x+2)
Factor 3x^2+6x into 3x(x+2)
2( 3x(x+2)+1(x+2) )
factor out common factor (x+2)
2(x+2)(3x+1)
=>
6x^2+14x+4=2(x+2)(3x+1)
Given:
hours parking charge
4 5.50
7 7.75
7 - 4 = 3 hours
7.75 - 5.50 = 2.25
2.25 / 3 = 0.75
0.75 is the change in amount for every hour spent. It is the variable unit rate
4 hours is 5.50.
Cost of parking for 3 hours is: 5.50 - 0.75 = 4.75
0.75 x 4 hours = 3
5.50 - 3 = 2.5 fixed charge.
total parking charge: y = 2.50 + 0.75x
B. x < -4
-2(3x + 6) > 4(x + 7)
-6x - 12 > 4x + 28
-10x > 40
X < -4
3 less than the quotient of a number y and 4
3 < y / 4
3 < y/4
x 4 x 4
12 < y
