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makvit [3.9K]
3 years ago
5

what is the answer for this question and can tell me how to do this problem too. 791 + 11 > 959 − 13

Mathematics
1 answer:
kompoz [17]3 years ago
4 0

Answer:

The question is false

Step-by-step explanation:

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What are the potential solutions to the equation 2ln(x+3)=0
skad [1K]
2\ln(x+3)=0\implies \ln(x+3)^2=0\implies e^{\ln(x+3)^2}=e^0\implies (x+3)^2=1

Expanding the left side gives

x^2+6x+9=1\implies x^2+6x+8=0\implies (x+4)(x+2)=0

which gives two solutions, x=-4 and x=-2. But if x=-4, then \ln(x+3)=\ln(-1), but this number isn't real, so x=-4 is an extraneous solution. Meanwhile if x=-2, you get \ln(-2+3)=\ln1=0, so this solution is correct.

"Potential solutions" might refer to both possibilities, but there is only one actual (real) solution.
4 0
3 years ago
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A. 3/2

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2 years ago
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IRINA_888 [86]
I think yes because the number are not all the same
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Anestetic [448]

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I learned this last month

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A stock's value was projected to close at $400. The stock actually closed at a value of $328. What is the percent error of the s
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