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3 years ago

what is the answer for this question and can tell me how to do this problem too. 791 + 11 > 959 − 13

Mathematics

1 answer:

kompoz [17]3 years ago

4 0

Answer:

The question is false

Step-by-step explanation:

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How many different tables of 4 can you make from 16 potential bridge players? How many different tables if 4 players insist on p

Nadusha1986 [10]

4 tables. 4*4 is 16, meaning that even if 4 players want to sit together it doesn't make a difference. With 16 players and 4 at a table we are going to need 4 tables.

8 0

3 years ago

Read 2 more answers

Complete the solution of the equation. Find the value of y when x equals -10

Artist 52 [7]

Y=2

EXPLANATION:

2(-10)-9y=-38

-20-9y=-38

-9y=-18

y=2

5 0

3 years ago

Can someone help with these two questions? dont worry if its wrong!

nevsk [136]

Answer:

1)8&3/4 CUP FLOUR

2)26 KIDS CAN GO ..

Step-by-step explanation:

1) one batch=2 1/2 cup flour

therefore batch required in 3 1/2 batch= 5/2×7/2=35/4

=8&3/4cup flour

2)No. of kids can go for $60=8

therefore,no. of kids can go in $1=8/60

Therefore,no. of kids can go in $195=8/60×195=26 kids.

6 0

2 years ago

Read 2 more answers

Find the value of X round your answer to the nearest tenths

vlabodo [156]

Answer:

x = 17.9

Step-by-step explanation:

$tan40^{0} =\frac{15}{x}$

$x=\frac{15}{tan40^{0} } =17.88$

rounded: 17.9

Hope this helps

6 0

2 years ago

10. A random sample of 10 fibers is taken from a collection of 92 fibers that consists of 43 fibers of polymer A, 17 fibers of p

vazorg [7]

Answer:

0.1150 = 11.50% probability that the sample does not contain any fibers of polymer B

Step-by-step explanation:

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

Fibers are chosen without replacement, which means that we use the hypergeometric distribution.

92 fibers means that $N = 92$

Sample of 10 means that $n = 10$

No polymeter B which means that $x = 0$

17 fibers of polymeter B which means that $k = 17$

a. What is the probability that the sample does not contain any fibers of polymer B

This is P(X = 0).

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 0) = h(0,92,10,17) = \frac{C_{17,0}*C_{75,10}}{C_{92,10}} = 0.1150$

0.1150 = 11.50% probability that the sample does not contain any fibers of polymer B

4 0

2 years ago