Answer: - 0.28
Explanation:
1) Expected value: is the weighted average of the values, being the probabilities the weight.
That is: ∑ of prbability of event i × value of event i.
In this case: (probability of getting 2 or 12) × (+6) + (probability of gettin 3 or 11) × (+2) + (probability of any other sum) × (-1).
2) Sample space:
Sum Points awarded
1+ 1 = 2 +6
1 + 2 = 3 +2
1 + 3 = 4 -1
1 + 4 = 5 -1
1 + 5 = 6 -1
1 + 6 = 7 -1
2 + 1 = 3 +2
2 + 2 = 4 -1
2 + 3 = 5 -1
2 + 4 = 6 -1
2 + 5 = 7 -1
2 + 6 = 8 -1
3 + 1 = 4 -1
3 + 2 = 5 -1
3 + 3 = 6 -1
3 + 4 = 7 -1
3 + 5 = 8 -1
3 + 6 = 9 -1
4 + 1 = 5 -1
4 + 2 = 6 -1
4 + 3 = 7 -1
4 + 4 = 8 -1
4 + 5 = 9 -1
4 + 6 = 10 -1
5 + 1 = 6 -1
5 + 2 = 7 -1
5 + 3 = 8 -1
5 + 4 = 9 -1
5 + 5 = 10 -1
5 + 6 = 11 +2
6 + 1 = 7 -1
6 + 2 = 8 -1
6 + 3 = 9 -1
6 + 4 = 10 -1
6 + 5 = 11 +2
6 + 6 = 12 +6
2) Probabilities
From that, there is:
- 2/36 probabilities to earn + 6 points.
- 4/36 probabilites to earn + 2 points
- the rest, 30/36 probabilities to earn - 1 points
3) Expected value = (2/36)(+6) + (4/36) (+2) + (30/36) (-1) = - 0.28
Answer:
Step-by-step explanation:
Hello, please consider the following.
Hope this helps.
Do not hesitate if you need further explanation.
Thank you
In order to solve this we need to make on part of both statements equal.
Since 12 is divisible by 6 lets do that.
Multiply everything in the second package by 2.
It then becomes 6 pairs for $12.
So now have have 6 or 8 pairs for $12.
You are getting a different amount for the same price therefore they are not proportional.
Lovee the nails!!!
my guess is x=28
hope this helps!!! :))
Answer:
The equation is <u>sale price</u>=p and the original price is $41.09.
.70
Step-by-step explanation:
sale price= (1-.30)p
<u>sale price=.70</u>p
.70 .70
<u>sale price</u>=p
.70
<u>28.76</u>=p
.70
$41.09=p
