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3 years ago

Measure the length of the paper clip to the nearest tenth of a centimeter.

Mathematics

2 answers:

Yuki888 [10]3 years ago

6 0

3 because it is a lot closer to 3 than 4. Plus it isn’t even close to the 1/2 centimeter mark.

Solnce55 [7]3 years ago

3 0

3 cm since the end is closer to the 3 than it is to 4

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Please answer correctly !!!!!!!!!!!!!! Will Mark Brianliest !!!!!!!!!!!!!!!!!!!

alexgriva [62]

Answer:

x = 30

Step-by-step explanation:

well from the theorem we have

$\frac{15}{3}=\frac{x}{6}$

yes i know you could say that the right way is

$\frac{3}{15}=\frac{6}{x}$

well if you notice they are the same only that in my way the x is in the numerator which means it will be far easier to know it's value :)

$\frac{15}{3}=\frac{x}{6}\\\\5=\frac{x}{6}\\\\6[5]=6[\frac{x}{6}]\\\\30=x$

8 0

3 years ago

Ms. Gadget car broke down on the turnpike. Acme town Ig charged $30 plus $3 per mile to tow the car. If ms. Gadget paid $162, ho

Reil [10]

The equation would be 30+3m=162 then you solve the problem

4 0

2 years ago

Solve the following quadratic equation 3×^2-5=0

coldgirl [10]

ANSWER:

X= radical 15/3 , radical -15/3

Decimal form:

X=1.29099444
X=-1.29099444

MARK ME BRAINLIEST PLEASE

8 0

3 years ago

What is the inverse function of f(x)=2x-1

Goshia [24]

Step-by-step explanation:

Given

f(x) = 2x - 1

f^-1 (x) = ?

Now

Let y = f(x)

or y = 2x - 1

Interchanging the role of x and y

x = 2y - 1

x + 1 = 2y

y = x + 1

Therefore f^-1(x) = x + 1

Hope it will help you :)

8 0

4 years ago

If the numbers 4, 5 and 6 are each used exactly once to replace the letters in the expression A ( B − C ), what is the least pos

guapka [62]

Answer:

The least possible result is -10.

Step-by-step explanation:

Given the numbers 4, 5 and 6 are to be chosen one of the letters A, B or C.

First of all,

Let A = 4, B = 5 and C = 6

$A(B-C) = 4 \times (5-6) = 4 \times -1 = -4$

Let A = 4, B = 6 and C = 5

$A(B-C) = 4 \times (6-5) = 4 \times 1 = 4$

Let A = 5, B =4 and C = 6

$A(B-C) = 5 \times (4-6) = 5 \times -2 = -10$

Let A = 5, B = 6 and C = 4

$A(B-C) = 4 \times (6-4) = 4 \times 2 = 8$

Let A = 6, B = 4 and C = 5

$A(B-C) = 6 \times (4-5) = 6 \times -1 = -6$

Let A = 6, B = 5 and C = 4

$A(B-C) = 6 \times (6-5) = 6 \times 1 = 6$

Summarizing the above values in the form of a table:

$\begin{center}\begin{tabular}{ c c c c}A & B & C & A(B-C)\\ 4 & 5 & 6 & -4\\ 4 & 6 & 5 & 4\\ 5 & 4 & 6 & -10\\ 5 & 6 & 4 & 10\\ 6 & 4 & 5 & -6\\ 6 & 5 & 4 & 6\end{tabular}\end{center}$

So, the least possible result is -10.

3 0

3 years ago