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xxTIMURxx [149]
3 years ago
8

What's is 57 divided by 858 using partial quote

Mathematics
1 answer:
Elena L [17]3 years ago
5 0
18r3. Sorry if I got it wrong but hopefully it is right.
You might be interested in
No links please. Fill in the blanks. 67ns=[?]x10^[?]s
cluponka [151]

Using scientific notation, it is found that:

67 ns = 6.7 \times 10^{-8}s

<h3>What is scientific notation?</h3>

A number in scientific notation is given by:

a \times 10^b

With the base being a \in [1, 10).

In this problem, the amount is of 67 ns.

Each ns has 10^{-9} seconds, hence:

67ns = 67 \times 10^{-9}s

We want the base between 1 and 10(exclusive), hence, we move the decimal digit one digit to the left and add one to the exponent, and the representation is:

67 ns = 6.7 \times 10^{-8}s

You can learn more about scientific notation at brainly.com/question/16394306

7 0
2 years ago
What the round to the biggest place value for 2,356
Wewaii [24]
Round to the biggest place value, 2,356 in the thousands place so the thousandths place is the greatest value there so 2,356 rounded to the nearest thousandths is 2,000
7 0
3 years ago
Read 2 more answers
Determine which value best represents each point on the number line below?
DaniilM [7]
A= 0.5 B=1 C=2.5 D=3.5
5 0
3 years ago
Let $f(x) = x^2$ and $g(x) = \sqrt{x}$. Find the area bounded by $f(x)$ and $g(x).$
Anna [14]

Answer:

\large\boxed{1\dfrac{1}{3}\ u^2}

Step-by-step explanation:

Let's sketch graphs of functions f(x) and g(x) on one coordinate system (attachment).

Let's calculate the common points:

x^2=\sqrt{x}\qquad\text{square of both sides}\\\\(x^2)^2=\left(\sqrt{x}\right)^2\\\\x^4=x\qquad\text{subtract}\ x\ \text{from both sides}\\\\x^4-x=0\qquad\text{distribute}\\\\x(x^3-1)=0\iff x=0\ \vee\ x^3-1=0\\\\x^3-1=0\qquad\text{add 1 to both sides}\\\\x^3=1\to x=\sqrt[3]1\to x=1

The area to be calculated is the area in the interval [0, 1] bounded by the graph g(x) and the axis x minus the area bounded by the graph f(x) and the axis x.

We have integrals:

\int\limits_{0}^1(\sqrt{x})dx-\int\limits_{0}^1(x^2)dx=(*)\\\\\int(\sqrt{x})dx=\int\left(x^\frac{1}{2}\right)dx=\dfrac{2}{3}x^\frac{3}{2}=\dfrac{2x\sqrt{x}}{3}\\\\\int(x^2)dx=\dfrac{1}{3}x^3\\\\(*)=\left(\dfrac{2x\sqrt{x}}{2}\right]^1_0-\left(\dfrac{1}{3}x^3\right]^1_0=\dfrac{2(1)\sqrt{1}}{2}-\dfrac{2(0)\sqrt{0}}{2}-\left(\dfrac{1}{3}(1)^3-\dfrac{1}{3}(0)^3\right)\\\\=\dfrac{2(1)(1)}{2}-\dfrac{2(0)(0)}{2}-\dfrac{1}{3}(1)}+\dfrac{1}{3}(0)=2-0-\dfrac{1}{3}+0=1\dfrac{1}{3}

6 0
3 years ago
A group of 12 students is deciding whether to go to the science center or the zoo. Science center tickets are 3 for $36.75 and z
Naya [18.7K]

ANSWER:

$6

ExPLANATION:

Step 1:

36.75 × 4 = 147

Step 2:

51 × 3 = 153

Step 3:

153 - 147 = 6

3 0
3 years ago
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