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Lisa [10]
3 years ago
6

If the numbers 4, 5 and 6 are each used exactly once to replace the letters in the expression A ( B − C ), what is the least pos

sible result?
Mathematics
1 answer:
guapka [62]3 years ago
3 0

Answer:

The least possible result is <em>-10</em>.

Step-by-step explanation:

Given the numbers 4, 5 and 6 are to be chosen one of the letters A, B or C.

First of all,

Let A = 4, B = 5 and C = 6

A(B-C) = 4 \times (5-6) = 4 \times -1 = -4

Let A = 4, B = 6 and C = 5

A(B-C) = 4 \times (6-5) = 4 \times 1 = 4

Let A = 5, B =4 and C = 6

A(B-C) = 5 \times (4-6) = 5 \times -2 = -10

Let A = 5, B = 6 and C = 4

A(B-C) = 4 \times (6-4) = 4 \times 2 = 8

Let A = 6, B = 4 and C = 5

A(B-C) = 6 \times (4-5) = 6 \times -1 = -6

Let A = 6, B = 5 and C = 4

A(B-C) = 6 \times (6-5) = 6 \times 1 = 6

Summarizing the above values in the form of a table:

\begin{center}\begin{tabular}{ c c c c}A & B & C & A(B-C)\\ 4 & 5 & 6 & -4\\  4 & 6 & 5 & 4\\  5 & 4 & 6 & -10\\  5 & 6 & 4 & 10\\  6 & 4 & 5 & -6\\ 6 & 5 & 4 & 6\end{tabular}\end{center}

So, the least possible result is <em>-10</em>.

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