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vova2212 [387]
3 years ago
11

3x-7y=2 solve for x. Can you show how you do it?

Mathematics
1 answer:
guajiro [1.7K]3 years ago
5 0
3x-7y=2 ; 3x=2+7y x=2x+7y/3
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Write a point slope form of the line that passes through (6,1) and it is parallel to a line with a slope of -3
Dafna1 [17]

Answer:

Step-by-step explanation:

y - 1 = -3(x - 6)

8 0
3 years ago
Vita has a pice of rope that is 5 meters long. She cuts the rope into pieces that are each 1/3 meter long. How many pieces does
sp2606 [1]
Normally you would divide something like this by the cuts made. So if there were cuts of 2 inches on a 10 inch rope, then you should divide 10 by 2. It's the same with this:
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4 0
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Triangle LMN and QRS are similar. Find x.
solong [7]
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3 years ago
Help with #7 be clear and show work !
Alex777 [14]
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4 0
3 years ago
Read 2 more answers
Find the deriative dy/dx for y=x^2-2x/x^3+3
vaieri [72.5K]

Answer:

\frac{dy}{dx}=(\frac{(2x-2)(x^3+3)-(x^2-2x)(3x^2)}{(x^3+3)^2})

Step-by-step explanation:

So we want to find the derivative of the rational equation:

y=\frac{x^2-2x}{x^3+3}

First, recall the quotient rule:

(\frac{f}{g})'=\frac{f'g-fg'}{g^2}

Let f be x^2-2x and let g be x^3+3.

Calculate the derivatives of each:

f=x^2-2x\\f'=2x-2

g=x^3+3\\g=3x^2

So:

\frac{dy}{dx}=(\frac{x^2-2x}{x^3+3})'

Use the above format:

\frac{dy}{dx}=\frac{f'g-fg'}{g^2}\\\frac{dy}{dx}=(\frac{(2x-2)(x^3+3)-(x^2-2x)(3x^2)}{(x^3+3)^2})

And that's our answer :)

(If you want to, you can also expand. However, no terms will be canceled.)

8 0
3 years ago
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