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2 years ago

There are 600 students in a school. The ratio of boys to girls is 3:5. How many boys and how many girls are there?

Mathematics

1 answer:

vitfil [10]2 years ago

8 0

Add both amounts together but both multiplied by an unknown value, x.
3x+5x=600
8x=600
8x/8=600/8
x=75
3(75)=225
225 boys
5(75)=375
375 girls

225 boys and 375 girls

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Factor completely, then place the answer in the proper location on the grid. 6x2 - 3x - 30

AVprozaik [17]

Answer:

3(2x-5)(x+2)

Step-by-step explanation:

Factor out the 3.

3(2x²-x-10)

Factor the remaining.

3(2x-5)(x+2)

(I don‘t know what grid they’re talking about.)

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3 years ago

Point B ∈ AC . Points K, M, N, and P are the midpoints of AB , AC , MC , and NC , respectively. Write a congruency statement for

Ann [662]

Answer:

AK = BK, AM = CM, MN = CN, NP = CP

Step-by-step explanation:

B ∈ AC

Points K, M, N, and P are the midpoints of AB , AC , MC , and NC

Then

K is midpoint of AB ⇒

AK = BK

M is midpoint of AC ⇒

AM = CM

N is midpoint of MC ⇒

MN = CN

P is midpoint of NC ⇒

NP = CP

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2 years ago

Solve the inequality both algebraically and graphically. Draw a number line graph of the solution and give interval notation.

Lemur [1.5K]

Finding the solution algebraically

To answer this inequality, we can follow the next steps:

1. Multiply by 7 both sides of the inequality:

$7\cdot\frac{(x-7)}{2}$

2. Multiply by 2 both sides of the inequality:

$7\cdot2\cdot^{\cdot}\frac{(x-7)}{2}$

3. Apply the distributive property at the left side of the inequality:

$7\cdot x-7\cdot7$

4. Add 49 to both sides of the inequality:

$7x-49+49$

5. Finally, divide both sides of the inequality by 7:

$\frac{7x}{7}$

We can graph this inequality in the number line as follows:

Notice the parenthesis indicating that the solution is the number below 131/7 (but not equal to 131/7). In interval notation the solution is:

$(-\infty,\frac{131}{7})$ $(-\infty,18\frac{5}{7})$

Or, approximately:

$(-\infty,18.7142857143)$

The number 131/7 in decimal is equivalent to 18.7142857143, so the graph of the solution is given by graph A (we can see that there are seven divisions between 18 and 19; since we have that the shaded division is in the 5th division, then, we have 5/7 = 0.714285714286, that is, the decimal part of the above number).

We can express the number 131/7 as a mixed number as follows:

$\frac{131}{7}=\frac{126}{7}+\frac{5}{7}=18+\frac{5}{7}=18\frac{5}{7}$

Again, notice also the symbol for the left part of the interval notation is a parenthesis since the interval is open at the point 131/7 = 18 + 5/7.

Finding the solution graphically

To find the solution graphically, we can represent the inequality as two lines as follows:

$y=\frac{x-7}{2},y=\frac{41}{7}$

Then, if we graph the first line, we can find the x- and the y-intercepts to find two points to graph the line. We have that the x- and the y-intercepts are:

The x-intercept is (that is, when y = 0):

$0=\frac{x-7}{2}\Rightarrow x-7=0\Rightarrow x=7$

Then, the x-intercept is (7, 0), and the y-intercept (the point on the graph when x = 0) is:

$y=\frac{x-7}{2}\Rightarrow y=\frac{0-7}{2}\Rightarrow y=-\frac{7}{2}$

Then, the y-intercept is (0, -7/2).

The other line is given by:

$y=\frac{41}{7}=\frac{35}{7}+\frac{6}{7}=5\frac{6}{7}$

With this information, we can graph both lines:

And we can see that the point where the two lines coincide is:

$(\frac{131}{7},\frac{41}{7})$

Then, the values for x of the line (x-7)/2 [that is, the values of y = (x-7)/2] that are less than y = 41/7, represented as:

$\frac{(x-7)}{2}$

Are those values of x less than 131/7, or the solution is also (we express the solution as a fraction or a mixed number as follows) (the same solution):