Anyone know how the graph is suppose to go?
1 answer:
Remark
You have given the second best answer. Your answer is |x|<1. You should have open circles at 1 and - 1.
Solution
I have enclosed a graph that is not a number line. You could confine yourself to a number line just by tracing out the blue solution (which is the answer you want)
The red solution is what you did.
The blue solution does not include x = 1 nor does it include x = - 1. The number line would show 1 < x < ∞ and -∞ < x < -1
You have given the second best answer. Your answer is |x|<1. You should have open circles at 1 and - 1.
Solution
I have enclosed a graph that is not a number line. You could confine yourself to a number line just by tracing out the blue solution (which is the answer you want)
The red solution is what you did.
The blue solution does not include x = 1 nor does it include x = - 1. The number line would show 1 < x < ∞ and -∞ < x < -1
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Answer:
Option (2)
Step-by-step explanation:
Parent function has been given as,
f(x) =
When translated by 3 units left,
f(x + 3) =
g(x) =
If the translated function is stretched vertically by a scale factor = k
New function will be,
g'(x) =
Since a point (1, 4) passes lies on the transformed function.
g'(1) =
4 = 2k
k = 2
Therefore, transformed function represents the translation by 3 units in the negative side of the x-axis and stretched vertically by 2 units.
Option (2) will be the answer.