Anyone know how the graph is suppose to go?
1 answer:
Remark
You have given the second best answer. Your answer is |x|<1. You should have open circles at 1 and - 1.
Solution
I have enclosed a graph that is not a number line. You could confine yourself to a number line just by tracing out the blue solution (which is the answer you want)
The red solution is what you did.
The blue solution does not include x = 1 nor does it include x = - 1. The number line would show 1 < x < ∞ and -∞ < x < -1
You have given the second best answer. Your answer is |x|<1. You should have open circles at 1 and - 1.
Solution
I have enclosed a graph that is not a number line. You could confine yourself to a number line just by tracing out the blue solution (which is the answer you want)
The red solution is what you did.
The blue solution does not include x = 1 nor does it include x = - 1. The number line would show 1 < x < ∞ and -∞ < x < -1
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Answer:
Use demos or a graphing calc.
Step-by-step explanation:
Answer:
(a) [8, 14]
(b)
(c)See attachment
Step-by-step explanation:
We want to choose a value of x within 3 units of 11.
(a)Now, 11-3=8 and 11+3=14
The possible values of x ranges is in the closed interval [8,14]
(b) Since x is within 3 units of 11., we have:
Solving the absolute inequality
(c)To draw the number line, we use a closed dot since we have the less than or equal to sign.
