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NISA [10]
3 years ago
7

Need help with this Question

Mathematics
1 answer:
Sloan [31]3 years ago
5 0

Answer:

-5 > -18

Step-by-step explanation:

-5 is greater because it has less negative value than -18.

The greater the number on negative, the lesser its value.

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Kyle is a basketball player. His bottle was full at the beginning of the game. At the end of the first quarter, he drank 5/7 of
gizmo_the_mogwai [7]

Answer:

1 4/35

Step-by-step explanation:

All I did was do 5/7 + 2/5.

5 0
3 years ago
2b-5/b-2 = 3/b+2<br><br><br><br> SOLVE
Deffense [45]
Cross multiply:-

3(b - 2) = (2b - 5)(b + 2)

3b - 6 = 2b^2 + 4b - 5b - 10

2b^2 - 4b - 4 = 0

b^2 - 2b - 2 = 0

b = 2.73, -0.73  Answer
7 0
3 years ago
Luis has $20.He buys 4 cans of tennis balls and gets $8 back as change .How much did one can of tennis balls cost?
WARRIOR [948]

Answer:

20-8 = 12 , he waste $12 if he got 4 cans 12 divide by 4 equal 3 so the one can cost $3

Step-by-step explanation:

3 0
4 years ago
Read 2 more answers
A student wrote and simplified an expression for the perimeter of the rectangle. (Using the picture provided.)
Nookie1986 [14]

Answer:

It’s 10n+12

They put the 2 n’s as an exponent

Step-by-step explanation:

3 0
3 years ago
What is the perimeter of this quadrilateral?<br> (5,5)<br> (2, 4)<br> (4, 1)<br> (6, 1)
lbvjy [14]

~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_1}{5}~,~\stackrel{y_1}{5})\qquad B(\stackrel{x_2}{2}~,~\stackrel{y_2}{4}) ~\hfill AB=\sqrt{[ 2- 5]^2 + [ 4- 5]^2} \\\\\\ AB=\sqrt{(-3)^2+(-1)^2}\implies \boxed{AB=\sqrt{10}} \\\\[-0.35em] ~\dotfill\\\\ B(\stackrel{x_1}{2}~,~\stackrel{y_1}{4})\qquad C(\stackrel{x_2}{4}~,~\stackrel{y_2}{1}) ~\hfill BC=\sqrt{[ 4- 2]^2 + [ 1- 4]^2}

BC=\sqrt{2^2+(-3)^2}\implies \boxed{BC=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ C(\stackrel{x_1}{4}~,~\stackrel{y_1}{1})\qquad D(\stackrel{x_2}{6}~,~\stackrel{y_2}{1}) ~\hfill CD=\sqrt{[ 6- 4]^2 + [ 1- 1]^2} \\\\\\ CD=\sqrt{2^2+0^2}\implies \boxed{CD=2} \\\\[-0.35em] ~\dotfill\\\\ D(\stackrel{x_1}{6}~,~\stackrel{y_1}{1})\qquad A(\stackrel{x_2}{5}~,~\stackrel{y_2}{5}) ~\hfill DA=\sqrt{[ 5- 6]^2 + [ 5- 1]^2}

DA=\sqrt{(-1)^2+4^2}\implies \boxed{DA=\sqrt{17}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{\Large Perimeter}}{\sqrt{10}~~ + ~~\sqrt{13}~~ + ~~2~~ + ~~\sqrt{17}}~~ \approx ~~ 12.89

8 0
2 years ago
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