How many electrons can be on each ring of an atom?

1 answer:

4 0

Electron orbital shell is the correct terminology.

I'm not fresh on my chemistry, but size orbitals can hold increases as they move away from a cell. The maximum number of electrons that can occupy a specific energy level can be found using the following formula:

Electron Capacity = 2n²

<span>This means that the first shell can hold 2 electrons, the next 8, the third 18, the fourth 32, the fifth 50, and the sixth can hold 72.</span>

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The greenhouse effect is a result of

yaroslaw [1]

The answer would be D. absorption and radiation of energy in the atmosphere

4 0

3 years ago

If a 15 N box is lifted a distance of 3 m, how much work is done?

Naily [24]

Answer:

W=45J

Explanation:

W=Fd

W=15(3)=45

W=45J

7 0

3 years ago

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An electron moving horizontally to the right with speed v enters a region where a uniform magnetic field exists pointing into th

koban [17]

Answer:

W = 0

Explanation:

When an electron moves perpendicular to a uniform B-field. If the field is in a vacuum, the magnetic field B is the dominant factor determining the motion. Since the magnetic force F is perpendicular to the direction of travel, an electron follows a curved path in a magnetic field. The electron continues to follow this curved path until it forms a complete circle. Another way to look at this is that the magnetic force F is always perpendicular to velocity v, so that it does no work on the charged particle. The particle’s kinetic energy and speed thus remain constant. The direction of motion is affected but not the speed.

W = F*d*Cos ∅ = F*d*Cos 90° = 0 where d is the displacement.

The pic shown can help to understand the explanation.

5 0

3 years ago

A bungee jumper of mass 75kg is attached to a bungee cord of length L=35m. She walks oﬀ a platform (with no initial speed), reac

attashe74 [19]

Answer:

1. 77.31 N/m

2. 26.2 m/s

3. increase

Explanation:

1. According to the law of energy conservation, when she jumps from the bridge to the point of maximum stretch, her potential energy would be converted to elastics energy. Her kinetic energy at both of those points are 0 as speed at those points are 0.

Let g = 9.8 m/s2. And the point where the bungee ropes are stretched to maximum be ground 0 for potential energy. We have the following energy conservation equation

$E_P = E_E$

$mgh = kx^2/2$

where m = 75 kg is the mass of the jumper, h = 72 m is the vertical height from the jumping point to the lowest point, k (N/m) is the spring constant and x = 72 - 35 = 37 m is the length that the cord is stretched

$75*9.8*72 = 37^2k/2$

$k = (75*9.8*72*2)/37^2 = 77.31 N/m$

2. At 35 m below the platform, the cord isn't stretched, so there isn't any elastics energy, only potential energy converted to kinetics energy. This time let's use the 35m point as ground 0 for potential energy

$mv^2/2 = mgH$