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NikAS [45]
3 years ago
7

The amount of work done depends on what two things

Physics
1 answer:
fomenos3 years ago
8 0

mass and acceleration have a nice day


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Plz help >:
svlad2 [7]

Answer:

10m

Explanation:

The object distance and image distance is the same from the mirror. so the image is 5m behind the mirror.

5+5=10

5 0
3 years ago
What happens to the frequency and pitch of sound if the object making the sound moves away from you ?
Olin [163]

If you and the source of sound are moving apart, then the pitch (frequency) <em>you hear</em> is <em>lower</em> than the pitch (frequency) that's actually leaving the source.  

It doesn't matter whether you or the source is the one moving, only that the distance between you is increasing.

8 0
3 years ago
How dangerous or painful is the recoil of a shotgun?
skelet666 [1.2K]

Answer:

If you’re going to be shooting a lot, get a surplus flak jacket. This isn’t a bulletproof vest, it just stops fragmentation or shrapnel. More importantly, it absorbs shock. You can fire a 12 gauge shotgun all day long and you won’t feel sore at all.

hope it helps

3 0
3 years ago
By what factor will the electric force between two charged objects change if the charge on both objects is quadrupled
USPshnik [31]
D.16 with working shown below with respect to Coulomb’s law.
3 0
4 years ago
In a Broadway performance, an 84.5-kg actor swings from a R = 4.30-m-long cable that is horizontal when he starts. At the bottom
Arada [10]

Answer:

1.57772 m

Explanation:

M = Mass of actor = 84.5 kg

m = Mass of costar = 55 kg

v = Velocity of costar

V  = Velocity of actor

h_i = Intial height of actor = 4.3 m

g = Acceleration due to gravity = 9.81 m/s²

As the energy of the system is conserved

\frac{1}{2}MV^2=Mgh_i\\\Rightarrow V=\sqrt{2gh_i}\\\Rightarrow V=\sqrt{2\times 9.81\times 4.3}\\\Rightarrow V=9.18509\ m/s

As the linear momentum is conserved

MV=(m+M)v\\\Rightarrow v=\frac{MV}{m+M}\\\Rightarrow V=\frac{84.5\times 9.18509}{84.5+55}\\\Rightarrow v=5.56372\ m/s

Applying conservation of energy again

\frac{1}{2}(m+M)v^2=(m+M)gh_f\\\Rightarrow h_f=\frac{v^2}{2g}\\\Rightarrow h_f=\frac{5.56372^2}{2\times 9.81}\\\Rightarrow h_f=1.57772\ m

The maximum height they reach is 1.57772 m

3 0
3 years ago
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