Answer:
Area of shaded region = 16π in² (D)
Step-by-step explanation:
The question is incomplete without the diagram if the circles. Find attached the diagram used in solving the question.
Area of the smaller circle = 8π in²
Area of a circle = πr²
πr² = 8π
r² =8
r = √8 = 2√2
From the diagram, there are two smaller circles in a bigger circle.
The radius of the bigger circle (R) is 2times the radius of the smaller circle (r)
R = 2r
Area of bigger circle = πR²
= π×(2r)² = π×(2×2√2)²
= π×(4√2)² = π×16×(√2)²
Area of bigger circle = π×16×2
Area of bigger circle = 32π in²
Since there are two smaller circles in a bigger circle
Area of shaded region = Area of bigger circle -2(area of smaller circles)
Area of shaded region = 32π in² - 2(8π in²)
Area of shaded region = 32π in² - 16π in²
Area of shaded region = 16π in²
Answer:
See explanation
Step-by-step explanation:
Required
The average weight produced
The question is incomplete, as the required cells are not given and there are other missing details.
However, I will give a general explanation of calculating average in Excel
The required formula is:
=AVERAGE(Cell Range)
Assume the cells that contain the boxes are: cells A10 to A10010
The average will be calculated as:
=AVERAGE(A10:A10010)
Answer: f(x)=1-1.9x=x-2
Step-by-step explanation:
Big brain time.
Answer:
36 cups of Chex total.
Step-by-step explanation:
Well, he will obviously be using 12 cups of pretzels, so let's set that aside. For every cup of pretzels, there are 3 cups of chex. So, multiply 3x12. That will give you how much chex you will need.
So we are given the expression:
÷ 
When we divide fractions, we must flip the second term and change the sign to multiplication:

And then we multiply across:

Then we can break apart all of the like variables for simplification:

When we simplify variables through division, we subtract the exponent of the numerator from the exponent of the denominator. So we then have:



So then we multiply all of these simplified parts together:

So now we know that the simplified form of the initial expression is:
.