Answer:
Step-by-step explanation:
Give that:
the surface equation is 
from the family of traces in x = n given that , the equation can be represented as :
This represents a family of hyperbola for all values of n expects that n = ± 1
So, if n = ± 1,
Then
(y-z) (y+z) = 0
y = ± z
So, for n = ± 1, it is a pair of line for y = z, y = -z
Answer:
x = -1
Step-by-step explanation:
2(x – 2) + 6 = 0
~Distribute left side
2x - 4 + 6 = 0
~Combine like terms
2x + 2 = 0
~Subtract 2 to both sides
2x = -2
~Divide 2 to both sides
x = -1
Best of Luck!
Nate Natalie
5_2 2_2
10_4 4_4
15_6 6_6
Natalie walked 6 feet
Here i how I would do it:<span>f(x)=−<span>x2</span>+8x+15</span>
set f(x) = 0 to find the points at which the graph crosses the x-axis. So<span>−<span>x2</span>+8x+15=0</span>
multiply through by -1<span><span>x2</span>−8x−15=0</span>
<span>(x−4<span>)2</span>−31=0</span>
<span>x=4±<span>31<span>−−</span>√</span></span>
So these are the points at which the graph crosses the x-axis. To find the point where it crosses the y-axis, set x=0 in your original equation to get 15. Now because of the negative on the x^2, your graph will be an upside down parabola, going through<span>(0,15),(4−<span>31<span>−−</span>√</span>,0)and(4+<span>31<span>−−</span>√</span>,0)</span>
To find the coordinates of the maximum (it is maximum) of the graph, you take a look at the completed square method above. Since we multiplied through by -1, we need to multiply through by it again to get:<span>f(x)=31−(x−4<span>)2</span></span><span>
Now this is maximal when x=4, because x=4 causes -(x-4)^2 to vanish. So the coordinates of the maximum are (4,y). To find the y, simply substitute x=4 into the equation f(x) to give y = 31. So it agrees with the mighty Satellite: (4,31) is the vertex.</span>
