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vampirchik [111]
3 years ago
8

how does multiplying powers with the same base differ from multiplying powers with the same exponent but different bases?

Mathematics
1 answer:
statuscvo [17]3 years ago
4 0

Answer:

because exponents are just the amount of times the base number is multiplied by itself, changing the base number would change which number you are multiplying.

Step-by-step explanation:

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Complete the missing value in the solution to the equation.<br> y=-2x+4<br> y=-2
anygoal [31]

Answer:

X=3,y=-2

Step-by-step explanation:

This is a simultaneous equation question and we will have to solve using substitution method

So let's solve

y=-2x+4...(1)

y=-2....(2)

Let's substitute (2) into (1)

-2=-2x+4

Substrate 4 from both sides

-6=-2x

Divide both sides by-2

x=3

Substitute the value of x in (1)

y=-2(3)+4

y=-6+4

y=-2

Therefore x is 3,y is -2

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tan(E) (opposite side)/(adjacent side)
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4 years ago
Ahmed was invited at a party at his friend’s place at 20:00 hours. He left the house at 17:00 hours and travelled in his car at
WARRIOR [948]

Answer:

yes he did make it, when he left at 17:00 he had 3:00 hours to make it to the party. if you divide 200/80=2.5 meaning he's able to make it in 2.5 hours.

3 0
3 years ago
- 10 x + 4 = 11.3x i don’t know the answer
lubasha [3.4K]

Answer: x= 0.18779342

Step-by-step explanation:

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3 years ago
Find the limit , picture provided
V125BC [204]

Answer:

d. does not exist

Step-by-step explanation:

The given limits are;

\lim_{x \to 4} f(x) =5, \lim_{x \to 4} g(x) =0 and \lim_{x \to 4} h(x) =-2

We want to find

\lim_{x \to 4} \frac{f}{g}(x)= \lim_{x \to 4} \frac{f(x)}{g(x)}

By the properties of limits, we have;

\lim_{x \to 4} \frac{f}{g}(x)= \frac{\lim_{x \to 4} f(x)}{\lim_{x \to 4} g(x)}

This gives us;

\lim_{x \to 4} \frac{f}{g}(x)= \frac{5}{0}

Division by zero is not possible. Therefore the limit does not exist.

7 0
3 years ago
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