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mrs_skeptik [129]
3 years ago
15

What is the equation of this graphed line? (2,6) (-4,-6)

Mathematics
1 answer:
Norma-Jean [14]3 years ago
5 0

Answer:

y=2x + 2

Step-by-step explanation:

Δy

----- =\frac{-6-6}{-4-2} = \frac{-12}{-6}=2

Δx

y = mx + b

6 = 2(2) + b

6 = 4 + b

2 = b

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I don’t understand how to do this!!!! HELP
Margarita [4]
Let m = the total number of medals.

To find the total number of medals we can use either of the clues they gave us.

If Tara's team received 8 medals and that was 1/3 of the medals.  That must mean that:

m x 1/3 = 8
What number divided by 3 is 8? Well, that is 24.  Thus, the total number of medals is 24.

Note: we can check to see if 1/2 of 24 is 12, the total number of medals Jennifer team received, and it checks out!
6 0
3 years ago
What is the factor of ()=63−35
IgorC [24]

Answer:

the factor is this problem is

7(9 - 5)

Step-by-step explanation:

3 0
3 years ago
What is Evaluate 3(4 - 2)2
earnstyle [38]
Answer should be 12 3 times 4-2 is 6 times 2 is 12
5 0
3 years ago
A transformer increases the input voltage from 12V to 12,000V. What is the ratio of the number of wire turns on the primary coil
erma4kov [3.2K]

Answer:

\frac{n_p}{n_s}=\frac{1}{1000}

Step-by-step explanation:

Given voltage of primary coil is V_p=12V

And voltage of secondary coil is V_s=12,000V

A transformer is a device that contains primary and secondary coil. These coils are mounted on soft iron. The change in voltage depends upon the number of turns of primary coil (n_p) and secondary coil (n_s).

Following equation represents the relation between them.

\frac{V_s}{V_p} =\frac{n_s}{n_p}\\\\\frac{12,000}{12}=\frac{n_s}{n_p}\\\\1000=\frac{n_s}{n_p}

Then, ratio of the number of wire turns on the primary coil to the number of turns on the secondary coil is

\frac{n_p}{n_s}=\frac{1}{1000}

5 0
3 years ago
Write the complex number in polar form:
emmasim [6.3K]

9514 1404 393

Answer:

  2√30 ∠-120°

Step-by-step explanation:

The modulus is ...

  √((-√30)² +(-3√10)²) = √(30 +90) = √120 = 2√30

The argument is ...

  arctan(-3√10/-√30) = arctan(√3) = -120° . . . . a 3rd-quadrant angle

The polar form of the number can be written as ...

  (2√30)∠-120°

_____

<em>Additional comments</em>

Any of a number of other formats can be used, including ...

  (2√30)cis(-120°)

  (2√30; -120°)

  (2√30; -2π/3)

  2√30·e^(i4π/3)

Of course, the angle -120° (-2π/3 radians) is the same as 240° (4π/3 radians).

__

At least one app I use differentiates between (x, y) and (r; θ) by the use of a semicolon to separate the modulus and argument of polar form coordinates. I find that useful, as a pair of numbers (10.95, 4.19) by itself does not convey the fact that it represents polar coordinates. As you may have guessed, my personal preference is for the notation 10.95∠4.19. (The lack of a ° symbol indicates the angle is in radians.)

6 0
3 years ago
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