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zysi [14]
3 years ago
8

What is the answer of y=4x-6

Mathematics
2 answers:
galina1969 [7]3 years ago
8 0

Answer:

m=4

Step-by-step explanation:

miskamm [114]3 years ago
6 0
The answer of y=4x-6 would be m equals 4
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Which two values of x are roots of the polynomial below 3x²-3x+1​
ArbitrLikvidat [17]

Answer:  x  = (3 − i√3)/6 and (3 + i√3)/6

Step-by-step explanation:3x² − 3x + 1 = 0

∴ 3x² − 3x = -1

∴ x² − x = -1/3

∴ x² − x + (-1/2)² = (-1/2)² − 1/3

given x² + bx + (b/2)² = (x + b/2)²

∴ (x − 1/2)² = 1/4 − 1/3

∴ (x − 1/2)² = 3/12 − 4/12

∴ (x − 1/2)² = -1/12

∴ x − 1/2 = ±√(-1/12)

This tells us there are no real roots and if you need real number solutions we stop here

∴ x − 1/2 = ±i/(2√3)

∴ x − 1/2 = ±i√(3)/6

∴ x  = 1/2 ± i√(3)/6

∴ x  = 3/6 ± i√(3)/6

∴ x  = (3 − i√3)/6 and (3 + i√3)/6 <= the 2 complex roots

5 0
3 years ago
Read 2 more answers
Evaluate 3p/q when p=2and q=6
Ira Lisetskai [31]
So we know what the variables are already.

\frac{3*2}{6}

Now, 3 x 2 = 6.

So our fraction is 6/6.

6/6 is also equal to 1.
6 0
2 years ago
Read 2 more answers
How many times as heavy is the golden eagle as the northern bald eagle
alex41 [277]

Answer:

IDK but I need the points so

Step-by-step explanation:

7 0
2 years ago
Jack is drawing circles on a playground for a game. If he draws a circle with a radius 3 feet, what is the area of the circle, t
aev [14]

Answer:

28.2743 square feet (28 square feet, rounded)

Step-by-step explanation:

The area of a circle is given by the equation

Area = πr^2

Plug in 3 for the radius

Area= π(3)^2

3 squared is 9

Area= 9 π

Area= 28.2743 square feet

Rounded to the nearest square foot, the area of the circle is 28 square feet.

7 0
2 years ago
What is the solution to the system of equations?
Dovator [93]

Answer:

<h2>(-10, 2, 6)</h2>

Step-by-step explanation:

\left\{\begin{array}{ccc}x+3y+2z=8&(1)\\3x+y+3z=-10&(2)\\-2x-2y-z=10&(3)\end{array}\right\qquad\text{subtract both sides of the equations (1) from (2)}\\\\\underline{-\left\{\begin{array}{ccc}3x+y+3z=-10\\x+3y+2z=8\end{array}\right }\\.\qquad2x-2y+z=-18\qquad(4)\qquad\text{add both sides of the equations (3) and (4)}\\\\\underline{+\left\{\begin{array}{ccc}-2x-2y-z=10\\2x-2y+z=-18\end{array}\right}\\.\qquad-4y=-8\qquad\text{divide both sides by (-4)}\\.\qquad\qquad y=2\qquad\text{put the value of y to (1) and (3)}

\left\{\begin{array}{ccc}x+3(2)+2z=8\\-2x-2(2)-z=10\end{array}\right\\\left\{\begin{array}{ccc}x+6+2z=8&\text{subtract 6 from both sides}\\-2x-4-z=10&\text{add 4 to both sides}\end{array}\right\\\left\{\begin{array}{ccc}x+2z=2&\text{multiply both sides by 2}\\-2x-z=14\end{array}\right\\\underline{+\left\{\begin{array}{ccc}2x+4z=4\\-2x-z=14\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad\qquad3z=18\qquad\text{divide both sides by 3}\\.\qquad\qquad z=6\qquad\text{put the value of z to the first equation}

x+2(6)=2\\x+12=2\qquad\text{subtract 10 from both sides}\\x=-10

4 0
2 years ago
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