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ladessa [460]
3 years ago
9

PLEASE HELP ME

Mathematics
1 answer:
aliina [53]3 years ago
4 0

Answer: i think that it is 479.36

Step-by-step explanation:

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What transformation will take triangle GBC onto triangle ABC?<br><br> plz help it’s due today
umka2103 [35]

Answer:

Reflection of ΔGBC on side BC.

Step-by-step explanation:

Transformation is the process by which the orientation or dimension of a given shape or figure is adjusted by some method of processes to produce an image with a required property.

From the given diagram, triangles ABC and GBC are congruent, so that;

AC ≅ GC

AB ≅ GB

BC is a common side to both triangles

Therefore, the appropriate transformation that would take ΔGBC onto ΔABC is reflection on side BC.

4 0
3 years ago
Miriam took a taxi from her home to school. The taxi driver charged an initial fee of $4.50 plus $2 per mile. The total fare was
jekas [21]

Answer:

8 miles

Step-by-step explanation:

$20.50-$4.50= $16

$16/$2= 8 miles

Hope this helped! :)

7 0
3 years ago
Which is the approximate difference in the tenths between?
MArishka [77]

Answer:

0.4

Step-by-step explanation:

0.2 is too small,  and everything above 1.0 is too big, so by default, must be 0.4

4 0
3 years ago
Two crossroads, each of width 5 m, run at right angles through the centre of
DerKrebs [107]

550 sq m

Step-by-step explanation:

Step 1 :

The length of the first cross road the park  is 70 m

The width of the first cross road the park  is 5 m

So its area is 70 * 5  = 350 sq m

Step 2 :

The length of the second cross road the park  is 45 m

The width of the width cross road the park  is 5 m

So its area is 45 * 5 = 225 sq m

Step 3 :

The 2 cross roads intersect in the middle at an area of 5 * 5 = 25 sq m

This area is included in the computation of the area of both the cross roads and hence we need to subtract this area from the sum of the area of both the cross roads to obtain the actual area of cross roads in the park

So we have

the area of the cross roads inside the park = 350 + 225 - 25 = 550 sq m

8 0
3 years ago
Decide whether each expression is equivalent to 0.75t-21. 3/4t-21 3/4( t-21) 0.75( t-28) t-0.25t-21. Explain how you know
butalik [34]

Answer: expression 1,3 and 4 are equivalent to 0.75t-21.

Step-by-step explanation:

Expression 1

3/4t-21

= 0.75t - 21

Expression 2

3/4( t-21)

Multiply through by 0.75

= 0.75 ( t - 21 )

= 0.75t - 15.75

Expression 3

0.75( t-28)

Multiply through by 0.75

= 0.75t - 21

Expression 4

t-0.25t-21

let t = 1

1-0.25t - 21

= 0.75t - 21

expression 1,3 and 4 are equivalent to 0.75t-21.

6 0
3 years ago
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