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3 years ago

PLEASE HELP ME

Mathematics

1 answer:

aliina [53]3 years ago

4 0

Answer: i think that it is 479.36

Step-by-step explanation:

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A snail is moving at a rate of three inches every two minutes. How fast is the snail moving in feet per hour?

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Pls mark brainliest

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2 years ago

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Joan Messineo borrowed $47,000 at a 5% annual rate of interest to be repaid over 3 years. The loan is amortized into three eq

tester [92]

Answer:

a) The value of the Annual Payment is A=$17,258.80

b) Is the picture in the attachment file

c) As you can see it in the picture with each payment, balance comes down, due it is the interest base, Interest portion comes down too.

Step-by-step explanation:

a) First of all, we are going to list the Knowns: $VP=47000$ , $i=5$ % and $n=3$ , Then we can use $A=\frac{VP}{\frac{1-(1+i)^{-n} }{i} } =\frac{47000}{\frac{1-(1+0.05)^{-3} }{0.03} }=17258.80$ . So this is the value of the Annual Payment

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2 years ago

Evaluate -3x+4y when x=-7 y=-10

Alexus [3.1K]

Answer:

-19

Step-by-step explanation:

6 0

3 years ago

Please help if you can pic attatched

MA_775_DIABLO [31]

Answer:

Step-by-step explanation:

$CI=\left[\begin{array}{ccc}1&6&0\\0&1&2\\1&-1&3\end{array}\right] \left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right]$

Subtract row 3 from row 1:

$\left[\begin{array}{ccc}1&6&0\\0&1&2\\0&7&-3\end{array}\right] \left[\begin{array}{ccc}1&0&0\\0&1&0\\1&0&-1\end{array}\right]$

Subtract row 3 from 7 times row 2:

$\left[\begin{array}{ccc}1&6&0\\0&1&2\\0&0&17\end{array}\right] \left[\begin{array}{ccc}1&0&0\\0&1&0\\-1&7&1\end{array}\right]$

Divide row 3 by 17:

$\left[\begin{array}{ccc}1&6&0\\0&1&2\\0&0&1\end{array}\right] \left[\begin{array}{ccc}1&0&0\\0&1&0\\\frac{-1}{17} &\frac{7}{17} &\frac{1}{17} \end{array}\right]$

Subtract 2 of row 3 from row 2:

$\left[\begin{array}{ccc}1&6&0\\0&1&0\\0&0&1\end{array}\right] \left[\begin{array}{ccc}1&0&0\\\frac{2}{17} &\frac{3}{17} &\frac{-2}{17} \\\frac{-1}{17} &\frac{7}{17} &\frac{1}{17} \end{array}\right]$

Subtract 6 of row 2 from row 1:

$\left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right] \left[\begin{array}{ccc}\frac{5}{17}&\frac{-18}{17}&\frac{12}{17}\\\frac{2}{17} &\frac{3}{17} &\frac{-2}{17} \\\frac{-1}{17} &\frac{7}{17} &\frac{1}{17} \end{array}\right]$

$C^{-1}=\frac{1}{17} \left[\begin{array}{ccc}5&-18&12\\2&3&-2\\-1&7&1\end{array}\right]$

$C^{-1}b=\frac{1}{17} \left[\begin{array}{ccc}5&-18&12\\2&3&-2\\-1&7&1\end{array}\right]\left[\begin{array}{c}10&1&3\end{array}\right]=\left[\begin{array}{c}4&1&0\end{array}\right]$

3 0

3 years ago

What is the slope of this line −4x+7=2y−3

harina [27]

First, change this equation to y-intercept form:
-4x+7=2y-3
2y = -4x+10
y= -2x + 5
The slope is -2, which is the coefficient for x in y-intercept form.

3 0

3 years ago