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Wittaler [7]
3 years ago
13

Mr.Burn's class is taking aa field trip to the planetatium. The trip will $27 for each student. There are 18 students in his cla

ss . Use compatible numbers to estimate the total cost of the field trip
Mathematics
2 answers:
Savatey [412]3 years ago
8 0
27*18 = 486
The trip should cost around $486.
mojhsa [17]3 years ago
4 0
$27 x 18 students = 486 actual cost.

$30 x 10 students = 300 estimated total cost using compatible numbers.
$20 x 20 students = 400 estimated total cost using compatible numbers. (better option because it is nearer to the actual cost)

Compatible numbers are numbers that can easily be multiplied or divided using mental computation.

Compatible number for 27 and 18 can be: 30 and 20 OR 20 and 20 OR 30 and 10 OR 20 and 10.

However, there is a rule in multiplying the compatible numbers, when one number is increased the other number must be decreased.

So 27 can be increased to 30; while 18 can be decreased to 10 to get a product of 300.

27 can be decreased to 20; while 18 can be increased to 20 to get a product of 400.
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Solve the following system of equations. 3x+4y=12
Lesechka [4]

Answer:

(0,3) is the solution set for given system.

Step-by-step explanation:

Given that:

3x+4y=12  ------- eq1

2x-3y= -9 ------- eq2

Multiplying eq1 with 2 and eq2 with 3 we get:

6x + 8y = 24 --------- eq1

6x - 9y = -27 -------- eq2

Subtracting eq2 from 1 we get:

17y = 51

Dividing both sides by 17 we get:

y = 3

Putting value of 3 in eq1 we get:

3x + 4(3) = 12

3x + 12 = 12

3x = 0

Dividing both sides by 3

x = 0

So the solution set will be: (0,3)

i hope it will help you.

6 0
3 years ago
Which expression is equivalent to (4x^(3)y^(5))(3x^(5)y)^(2)
marshall27 [118]

Answer:

(4x^3y^5)(3x^5y)^2 = 36*x^{13}y^7

Step-by-step explanation:

Given

(4x^3y^5)(3x^5y)^2

Required

The equivalent expression

We have:

(4x^3y^5)(3x^5y)^2

Expand

(4x^3y^5)(3x^5y)^2 = 4x^3y^5*9x^{10}y^2

Further expand

(4x^3y^5)(3x^5y)^2 = 4*9*x^3*x^{10}y^5*y^2

Apply laws of indices

(4x^3y^5)(3x^5y)^2 = 36*x^{13}y^7

8 0
3 years ago
How can you quickly determine the number of roots a polynomial will have by looking at the equation?
Goryan [66]
First, you need to get delta which is b squared minus 4ac. If delta is higher than cero, the polynomial has two solutions, if it is less, the polynomial has no real solutions and if it is the same, it has one solution.
Although that is only for second grade ecuations
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3 years ago
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Karolina [17]
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3 years ago
Please help ASAPPPPP
iren [92.7K]

Answer:The third box

Step-by-step explanation:

You dont have to write the steps

6 0
3 years ago
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