All categories

4 years ago

From 5x^2-6x+8, subtract 3x^2-2x-4?

Mathematics

1 answer:

victus00 [196]4 years ago

8 0

$(5x^2-6x+8)-(3x^2-2x-4)=\\5x^2-6x+8-3x^2+2x+4=2x^2-4x+12$

You might be interested in

On a map, 1/2 inches represents 4/5 miles. what distance on the map represents one mile

pentagon [3]

5/8 inches should be the correct answer. Hope this helps!

6 0

3 years ago

Find each sum or difference. Then use front-

rosijanka [135]

The answer is 1, 240.

8 0

3 years ago

Read 2 more answers

Hannah needs two 2/3 -footboards and one 1 1/2-footboard for a woodshop project. For each question below, write your answer as a

m_a_m_a [10]

Answer:

total length: 2 1/6 ft Leftover: 4 5/6 ft How many: 2

Step-by-step explanation:

Total length: add 2/3ft and 1 1/2 ft together.

Leftover: Subtract 2 1/6ft from 6ft

How many: Multiply 2 1/6 by 2

7 0

2 years ago

A lap around Natalie's neighbourhood is 20 kilometres. Natalie ran 2 laps before

Fynjy0 [20]

I would say about 40 kilometers it’s ifs 20 around her neighborhood that 20+20=40 and walking tha rest made the question easier but yea 40

8 0

3 years ago

Eighty percent of the students graduating from high school in a small Iowa farm town attend college. The town's chamber of comme

anyanavicka [17]

Answer: 0.6368

Step-by-step explanation:

Given : The proportion of z-test for population mean : $\hat{p}= 0.80$

Sample size : $n=45$

We assume that this is normally distributed.

The test statistic for population proportion :-

$z=\dfrac{\hat{p}-p_0}{\sqrt{\dfrac{p_0(1-p_0)}{n}}}$

Now, for $p_0=0.82$ , we have

$z=\dfrac{0.80-0.82}{\sqrt{\dfrac{0.82(1-0.82)}{45}}}\\\\\approx-0.35$

By using the standard normal distribution table , the probability that at least 82% of the surveyed students will be attending college will be :-

$P(p\geq0.82)=P(z\geq-0.35)\\\\=1-P(z$

Hence, the probability that at least 82% of the surveyed students will be attending college = 0.6368

4 0

3 years ago