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3 years ago

Which integers are greater than -3 and less than 0?

2 answers:

4 0

-2 and -1 because negative numbers are the opposite of positive numbers so -2 and -1 are greater than -3 and less than zero.

Anon25 [30]3 years ago

3 0

Integers are whole numbers, both positive and negative. Therefore, all of the positive and negative whole numbers between these two numbers in a set will be your answer:

${-2, -1}$

Hope this helped, and have a nice day!

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Please help! Question on the picture

LekaFEV [45]

The answer for the problem is 5, 12

5 0

3 years ago

A polynomial P(x) and a divisor d(x) are given. Use long division to find a quotient Q(x) and the remainder R(x). Express P(x) i

Vilka [71]

It's a bit hard to explain but I hope this helps

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3 years ago

A patient weighs 195 pounds and requires 279 milligrams of medicine. What is the amount of medicine required by a patient weighi

WITCHER [35]

Answer:

186 milligrams

Step-by-step explanation:

195 130

—— ——

279 X

Cross multiply

195x = 36270

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6 0

3 years ago

For which conditions is p ∨ q false?

faust18 [17]

Answer:

p is false and q is false.

Step-by-step explanation:

Logic Disjunction

Assume p and q are propositions.

The disjunction of p and q, denoted by p ∨ q, is the proposition called "p or q".

The rule for the 'or' operation is: If any of the propositions are true, then the result is also true.

Thus, the disjunction p ∨ q is false when both p and q are false and is true otherwise.

The correct option is the last one:

p is false and q is false.

7 0

2 years ago

Read 2 more answers

Tags are placed to the left leg and right leg of a bear in a forest. Let A1 be the event that the left leg tag is lost and the e

Komok [63]

Answer:

0.75 = 75% probability that exactly one tag is lost, given that at least one tag is lost

Step-by-step explanation:

Independent events:

If two events, A and B, are independent, then:

$P(A \cap B) = P(A)*P(B)$

Conditional probability:

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: At least one tag is lost

Event B: Exactly one tag is lost.

Each tag has a 40% = 0.4 probability of being lost.

Probability of at least one tag is lost:

Either no tags are lost, or at least one is. The sum of the probabilities of these events is 1. Then

$p + P(A) = 1$

p is the probability none are lost. Each one has a 60% = 0.6 probability of not being lost, and they are independent. So

p = 0.6*0.6 = 0.36

Then

$P(A) = 1 - p = 1 - 0.36 = 0.64$

Intersection:

The intersection between at least one lost(A) and exactly one lost(B) is exactly one lost.

Then

Probability at least one lost:

First lost(0.4 probability) and second not lost(0.6 probability)

First not lost(0.6 probability) and second lost(0.4 probability)

$P(A \cap B) = 0.4*0.6 + 0.6*0.4 = 0.48$

Find the probability that exactly one tag is lost, given that at least one tag is lost (write it up to second decimal place).

$P(B|A) = \frac{0.48}{0.64} = 0.75$

0.75 = 75% probability that exactly one tag is lost, given that at least one tag is lost

8 0

2 years ago