Sue has one spin of the circular spinner shown below.
1 answer:
Answer:
Colour | Probability
YELLOW | 0.20
WHITE | 0.18
GREEN | 0.12
RED | 0.18
BLUE | 0.32
Step-by-step explanation:
The complete question is presented on the attached image to this solution.
From the image of the spinner and the given probabilities, the combination of YELLOW, WHITE and GREEN make up exactly half of the total space on the spinner.
0.2 + 0.18 + 0.12 = 0.50
Then, BLUE and RED make up the other half of the spinner.
Probability of landing on either BLUE or RED = 1 - 0.50 = 0.50
Let P(BLUE) = x and P(RED) = y
x + y = 0.50
Two of the lines shown on the diagram are diameters of the circle.
The first line that is a diameter splits the circle into two parts; (WHITE, YELLOW, GREEN) and (RED, BLUE).
From here, we have established that x + y = 0.50
The other line that is a diameter splits The circle into two part; (WHITE, BLUE) and (YELLOW, GREEN, RED)
From this other information,
P(WHITE) + P(BLUE) = 0.50
0.18 + x = 0.50
x = 0.50 - 0.18 = 0.32
P(YELLOW) + P(GREEN) + P(RED) = 0.50
0.20 + 0.12 + y = 0.50
y = 0.50 - 0.32 = 0.18
To check, x + y = 0.32 + 0.18 = 0.50 (Correct!!)
Hope this Helps!!!
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Answer:
The probability of the stick's weight being 2.33 oz or greater is 0.0041 or 0.41%.
Step-by-step explanation:
Given:
Weight of a given sample (x) = 2.33 oz
Mean weight (μ) = 1.75 oz
Standard deviation (σ) = 0.22 oz
The distribution is normal distribution.
So, first, we will find the z-score of the distribution using the formula:
Plug in the values and solve for 'z'. This gives,
So, the z-score of the distribution is 2.64.
Now, we need the probability .
From the normal distribution table for z-score equal to 2.64, the value of the probability is 0.9959. This is the area to the left of the curve or less than z-score value.
But, we need area more than the z-score value. So, the area is:
Therefore, the probability of the stick's weight being 2.33 oz or greater is 0.0041 or 0.41%.
Answer:
Using c++
Check the image for colors.
Step-by-step explanation:
#include <iostream>
using namespace std;
int main()
{
float length1,length2,width1,width2,area1,area2;
cout<<"length of Rectangle 1\n";
cin>>length1;
cout<<"\nwidth of Rectangle 1\n";
cin>>width1;
cout<<"\nlenght of Rectangle 2\n";
cin>>length2;
cout<<"\nwidth of Rectangle 2\n";
cin>>width2;
area1=length1*width1;
area2=length2*width2;
if (area1<area2)
{cout << "\nRectangle 2 has greater area";}
else {
if (area1>area2)
{cout << "\nRectangle 1 has greater area";}
else {cout << "\nAreas are the same";}
}
return 0;
}
