The ages of Olivia and her brother are 10 years and 11 years respectively
Let x₁, and x₂ be the ages of Olivia and her brother respectively.
Given that Olivia's brother is twice her age minus 9 years.
⇒ x₂ = 2x₁ - 9 → equation 1
Also given that Olivia's brother is as old as half the sum of the ages of Olivia and both of her 12-year-old twin brothers.
⇒ x₂ = 1/2 × (x₁ + 12) → equation 2
Using equation 1 in equation 2, we get
2x₁ - 9 = 1/2 × (x₁ + 12)
⇒ 4x₁ - 18 = x₁ + 12 (multiplying by 2 on both sides)
⇒ 4x₁ - x₁ = 12 + 18
⇒ 3x₁ = 30
⇒ x₁ = 10 (dividing by 3 on both sides)
Using the value of x₁, in equation 1,
⇒ x₂ = 2(10) - 9
⇒ x₂ = 20 - 9
⇒ x₂ = 11
Therefore the ages of Olivia and her brother are 10 years and 11 years respectively.
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Answer:
2(r+4)(r-4)
Step-by-step explanation
First, you want to factor out 2 from both terms, which gives you 2(r^2-16). Then you want to recognize that (r^2-16) is factorable into 2 terms. If you multiply (r+4) by (r-4) then you are given (r^2-16) as a result.
The boundaries:
x = 0, y = 8; y = 0, √x³ = = 8, x = 4
= π ( 64 x - 16 * 2 *√x^5 + x^4 / 4 ) =
= π ( 320 - 1024/5 + 64 ) =
179.2 π
Answer:
the answer is 1
Step-by-step explanation:
69 goes into 69, 1 time
It at the top all you had to do was divided bot ways you will get that answers
