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timama [110]
3 years ago
5

Write the expression 21a^3c^8/7a^5c^3

Mathematics
1 answer:
Ad libitum [116K]3 years ago
8 0
<span> (2a + 6 * 2)(3a + </span>3<span>)

hope this helps

</span>
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PLEASE PLEASE ANSWER THIS FOR ME I REALLY NEED TO UNDERSTAND IT
dexar [7]

Answer:

See answers below for explanations (answers are in bold)

Step-by-step explanation:

<u>Problem 1 (Top left):</u>

Assuming that the shape is an ellipse, we will use the formula A=πab where a and b are both half the major and minor axis respectively. Since a=9 and b=6, then we have A = π(9)(6) = 54π = 169.646 units^2 as our final answer

<u>Problem 2 (Top right):</u>

Again, we use the same equation as in Problem 1 but this time, a=12 and b=8, so we then have A = π(8)(12) = 96π = 301.593 units^2 as our final answer

<u>Problem 3 (Bottom left):</u>

We can make this irregular shape into a half-ellipse and a rectangle. We would find their separate areas and add them up. The area of the half-ellipse would be A=1/2πab. The value of "a" would be 13.8/2=6.9 since that's the length of the rectangle. The value of "b" would be 3.5, so that means the area of the half-ellipse would be A = 1/2(π)(6.9)(3.5) = 12.075π = 37.935 units^2.  The width and length of the rectangle are 5.4 and 13.8 respectively, so this means the area of the rectangle is 5.4*13.8 = 74.52 units^2. Combining both areas, we get 37.935+74.52 = 112.455 units^2 as our final answer

<u>Problem 4 (Bottom right):</u>

This irregular shape is an ellipse, but a circle is missing from its center. Thus, we must find the area of the circle and ellipse and then subtract the circle's area from the ellipse's area. For the area of the ellipse, a=(15.5/2)=7.75, and b=(7/2)=3.5, making its area A = π(7.75)(3.5) = 27.125π = 85.216 units^2. The area of a circle is A=πr² where "r" is the radius. The radius would be 7/2=3.5, making the circle's area A = π(3.5²) = 12.25π = 38.485 units^2. This means that the shaded area is 85.216-38.435 = 46.781 units^2  

6 0
3 years ago
Simplify each problem and expre<br> 1) (2 x 10°) + (5 x 109)
elixir [45]

<h2><u>PLEASE MARK BRAINLIEST!</u></h2>

Answer:

(2 · 10⁰) + (5 · 109)

= (2 · 0) + (5 · 109)

=    2     + (5 · 109)

=    2     +    545

=         547

Your answer is 547.

<em>I hope this helps!</em>

3 0
3 years ago
A survey of 542 consumers reveals that 301 favor the new design for a product. Construct a 90% confidence interval for the true
kodGreya [7K]

Answer:

The 90% confidence interval for the true proportion of all consumers who favor the design is (0.52, 0.59).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 542, \pi = \frac{301}{542} = 0.555

90% confidence level

So \alpha = 0.1, z is the value of Z that has a pvalue of 1 - \frac{0.1}{2} = 0.95, so Z = 1.645.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.555 - 1.645\sqrt{\frac{0.555*0.445}{542}} = 0.52

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.555 + 1.645\sqrt{\frac{0.555*0.445}{542}} = 0.59

The 90% confidence interval for the true proportion of all consumers who favor the design is (0.52, 0.59).

5 0
3 years ago
What is 4.25% as a decimal ​
Tcecarenko [31]

Answer:

0.0425

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
What is 14+10 written as an algebraic expression?
malfutka [58]

The mathematical statement of 14 + 10 is fourteen added to ten

<h3>What is 14+10 written as an algebraic expression?</h3>

The expression is given as:

14 + 10

The above expression is an algebraic expression, and it cannot be "rewritten" as an algebraic expression

Instead, it can be expressed as mathematical statement

The mathematical statement of 14 + 10 is fourteen added to ten

Read more about expression at

brainly.com/question/723406

#SPJ1

3 0
2 years ago
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