pemdas, so exponent first before multiply
4(x^1/2)=4x^2
this is different from
(4x)^1/2
so
times that by 4
4√x
Write the expression 21a^3c^8/7a^5c^3
1 answer:
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pemdas, so exponent first before multiply
4(x^1/2)=4x^2
this is different from
(4x)^1/2
so
times that by 4
4√x
Answer:
As the lines are not intersecting nor parallel, they must be skew.
Step-by-step explanation:
Question is incomplete, we consider the nearest match available online.
Parametric equations of two lines are:
L₁ : x=4t+2 , y = 3 , z =-t+1
L₂: x=2s+2 , y= 2s+5 , z = s+1
If lines are parallel then parametric coordinates must be equal scalar multiple of each other which s not true here.
If lines are intersecting then parametric coordinates must be equal for some value of t and s.
Hence the lines are not intersecting nor parallel, they must be skew.