Answer:
Length of the road parallel to the length of the park= 700m
Width of the road= 10m
Area of the road= l\times b=700m\times10m=7000m^2l×b=700m×10m=7000m
2
Length of the road parallel to the breadth of the park =300m
Width of the road= 10m
Area of this road= l\times b=300m\times10=3000m^2l×b=300m×10=3000m
2
Area of both the roads
=7000m^2+3000m^2-Area\ of\ the\ common\ portion\=7000m
2
+3000m
2
−Area of the common portion
=10000m^2-10m\times10m=10000m
2
−10m×10m
=10000m^2-100m^2=10000m
2
−100m
2
=9900m^2=0.99=9900m
2
=0.99
Area of the park = l\times bl×b
=700m\times300m=210000m^2=700m×300m=210000m
2
Area of the park excluding the roads
=210000m^2-9900m^2=210000m
2
−9900m
2
=200100m^2=20.01=200100m
2
=20.01
I need to find the x pls help and show work
$5040 after 40 years
hm... probably continuously i think ,
5+d>5−d
solve for d. First, isolate the d. Add d to both sides, and subtract 5 from both sides
5 (-5) + d (+d) > 5 (-5) - d (+d)
d + d > 5 - 5
2d > 0
Next, to isolate the d, divide 2 from both sides
2d/2 > 0/2
d > 0
d > 0, or (D) is your answer
hope this helps
