1. t = 7
2. t = 0
i think? although I’m not 100% sure
"He starts both trains at the same time. Train A returns to its starting point every 12 seconds and Train B returns to its starting point every 9 seconds". Basically, what you need to do is find the least common multiple. The least common multiple of 12 and 9 is 36, so the least amount of time, in seconds, that both trains will arrive at the starting points at the same time is 36 seconds.
Answer:
38.5
Step-by-step explanation:
First do 77/2 then you get 38.5, if anything is wrong please tell me!!