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e-lub [12.9K]
3 years ago
10

Write a polynomial (x+6)(x-2)(x-1)

Mathematics
2 answers:
sasho [114]3 years ago
7 0
<span>Write a polynomial (x+6)(x-2)(x-1)
</span><span><span><span>x<span><span>​3</span><span>​​</span></span></span>+3<span>x<span><span>​2</span><span>​​</span></span></span>−16x+12</span>I Hope this help</span>
shtirl [24]3 years ago
5 0
(x + 6) (x-2) (x-1)
 Let's rewrite the expression step by step.
 We have:
 We multiply the first two parentheses:
 (x ^ 2-2x + 6x-12) (x-1)
 We rewrite:
 (x ^ 2 + 4x-12) (x-1)
 Now we multiply the remaining parentheses:
 (x ^ 3 + 4x ^ 2-12x-x ^ 2-4x + 12)
 We rewrite
 (x ^ 3 + 3x ^ 2-16x + 12)
 Answer:
 The polynomial is:
 (x ^ 3 + 3x ^ 2-16x + 12)
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What is the rate of change of the function y = − 1/4 x + 1
scoray [572]

Answer:

-1/4

Step-by-step explanation:

Hello!

The rate of change is also known as the slope.

Standard equation of a line: y = mx + b

  • y: output
  • m:  slope
  • x: input
  • b: y-intercept

So, if we match the standard form to the given function:

  • y = mx + b
  • y = -1/4x + 1

-1/4 is m, or the rate of change.

8 0
2 years ago
Quiz TIme:
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Answer:

97

Step-by-step explanation:

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2 years ago
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Plz, help ASAP!!!!!!!!!!!!!!!
blsea [12.9K]

Answer: m∠QPR = 40

<h2>Step-by-step explanation:</h2>

Because PG is perpendicular to PS, it is safe to assume that angle QPS is 90 degrees.

(7x-9) + (4x +22) = 90

x = 7

Because we need to find the degrees of QPR, plug in the equation for that angle with the value of x we found.

7(7) - 9 = 40

m∠QPR = 40

8 0
3 years ago
Help me algebra are and circumference pls
Anvisha [2.4K]
The question is basically asking you how much area of the yard the pool takes up, in essence the area the pool takes up.

So we are going to find the area of the pool.

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6 0
2 years ago
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Use a calculator to find the value of each expression. Round your answer to the nearest hundredth.
inysia [295]

Answer:

Arcsin(1/5) = 0.20

Arcsin(-0.34) = -0.35

Arcsin(0.6) = 0.64

Step-by-step explanation:

Using a calculator we can find the value of each expression:

Arcsin(1/5) = 0.20135792079, rounding to the nearest hundredth we have that: Arcsin(1/5) = 0.20.

Arcsin(-0.34) = -0.346916897527, rounding to the nearest hundredth we have that: Arcsin(-0.34) = -0.35

Arcsin(0.6) = 0.643501108793, rounding to the nearest hundredth we have that: Arcsin(0.6) = 0.64

8 0
2 years ago
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