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3 years ago

Write a polynomial (x+6)(x-2)(x-1)

2 answers:

7 0

Write a polynomial (x+6)(x-2)(x-1)
x3+3x2−16x+12I Hope this help

shtirl [24]3 years ago

5 0

(x + 6) (x-2) (x-1)
Let's rewrite the expression step by step.
We have:
We multiply the first two parentheses:
(x ^ 2-2x + 6x-12) (x-1)
We rewrite:
(x ^ 2 + 4x-12) (x-1)
Now we multiply the remaining parentheses:
(x ^ 3 + 4x ^ 2-12x-x ^ 2-4x + 12)
We rewrite
(x ^ 3 + 3x ^ 2-16x + 12)
Answer:
The polynomial is:
(x ^ 3 + 3x ^ 2-16x + 12)

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earnstyle [38]

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3 years ago

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SSSSS [86.1K]

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3 years ago

A study conducted to determine the relationship between the age, x, in years of a certain brand of motorcycle and its value, y,

kirza4 [7]

Based on the equation, y = -750·x + 8500, the estimated value of a

motorcycle that is 5 years old is $4,750.

<h3>How can the given equation help to estimate the value of the motorcycle?</h3>

The regression equation that models the data is; y = -750·x + 8500

Where;

y = The value of the brand of motorcycle in dollars

x = The age of the motorcycle

When the motorcycle is 5 years old, we have;

x = 5

y = -750 × 5 + 8500 = 4750

Based on the equation, the estimated value of a motorcycle that is 5 years old, y = $4,750

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brainly.com/question/20475360

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3 years ago

What is the image of (0,-8)(0,−8) after a reflection over the line y=-xy=−x?

AnnZ [28]

Answer:

(8, 0 )

Step-by-step explanation:

under a reflection in the line y = - x

a point (x, y ) → (- y, - x ) , then

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2 years ago

The first term of an arithmetic sequence is -5, and the tenth term is 13. Find the common difference.

dlinn [17]

$\bf n^{th}\textit{ term of an arithmetic sequence} \\\\ a_n=a_1+(n-1)d\qquad \begin{cases} n=n^{th}\ term\\ a_1=\textit{first term's value}\\ d=\textit{common difference}\\[-0.5em] \hrulefill\\ a_1=-5\\ n=10\\ a_{10}=13 \end{cases} \\\\\\ a_{10}=a_1+(10-1)d\implies 13=-5+(10-1)d \\\\\\ 13=-5+9d\implies 18=9d\implies \cfrac{18}{9}=d\implies \boxed{2=d}$

7 0

3 years ago