What is the length of segment CE if AE = 15 inches and ED = 5 inches and EB = 3 inches?

Mathematics

1 answer:

Artemon [7]3 years ago

6 0

We have to determine the length of segment CE if AE = 15 inches and ED = 5 inches and EB = 3 inches.

Since ,we can observe that AB and CD are chords intersecting at point E.

Therefore, by intersecting chord theorem which states:

" When two chords intersect each other inside a circle, the products of their segments are equal"

So, $AE \times EB= CE \times ED$

$15 \times 3= CE \times 5$

$45= CE \times 5$

$CE = \frac{45}{5}$

CE = 9 inches.

So, the measure of segment CE is 9 inches.

So, Option B is the correct answer.

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