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scoray [572]
1 year ago
7

A small coffee shop sells freshly squeezed juices in a refrigerated unit with slots where juice is displayed. These slots are ca

lled facings. The manager of the coffee shop suspects that the distribution of juice sales is different than the distribution of facings for each type of juice, so the manager records the sales of each juice over a two-week period. The proportion of facings and the sales for each type of juice are shown in the tables.JuiceMangoOrangeApplePineappleGrapefruitGrapeProportion of Facings0.18750.2500.2500.1250.1250.0625JuiceMangoOrangeApplePineappleGrapefruitGrapeObserved Number of Sales23354612105(a) Construct a single bar chart that contains both the expected proportion of sales based on the proportion of facings and the observed proportion of sales for each type of juice.BoldItalicUnderline
Mathematics
1 answer:
fgiga [73]1 year ago
8 0

It should be noted that, according to the information provided, the single bar chart shows the projected proportion of sales based on the proportion of facings and the observed proportion.

Simply put, a bar chart is a bar graph. Rectangular bars that match the values shown are used to illustrate categorical data.

A bar chart, often known as a bar graph, is a diagram that displays categorical data as rectangular bars with heights or lengths proportional to the values they stand for. You can plot the bars either vertically or horizontally. A vertical bar chart may also be referred to as a column chart.

The bar chart's information reveals that the observed proportions for juice, mango, orange, apple, and pineapple are greater than the expected proportions.

Learn more about bar charts on:

brainly.com/question/17719884

#SPJ9

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1 year ago
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Brut [27]

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<u>Formula</u>

\textsf{Arc length}=r \theta

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\begin{aligned}\implies \textsf{Arc length} & =r \theta\\& = 5\left(\dfrac{3 \pi}{2}\right)\\& = \dfrac{15}{2} \pi \\& = 23.56\: \sf ft\:(2\:dp)\end{aligned}

\begin{aligned} \implies \textsf{Area of a sector}& =\dfrac{1}{2}r^2 \theta\\\\ & = \dfrac{1}{2}(5^2) \left(\dfrac{3 \pi}{2}\right)\\\\& = \dfrac{25}{2}\left(\dfrac{3 \pi}{2}\right)\\\\ & = \dfrac{75}{4} \pi \\\\& = 58.90 \: \sf ft^2\:(2\:dp)\end{aligned}

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