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Citrus2011 [14]
3 years ago
8

A spinner is divided into 5 equally sized segments colored blue, green, black, red, and yellow. Suppose you spin the wheel 2 tim

es. What is the probability of landing on the same color each time? Give your answer as an exact fraction and reduce the fraction as much as possible.
Mathematics
1 answer:
Blababa [14]3 years ago
7 0
1/5. The probability of landing on any color is 1/5. The probability of landing on one color two times in a row is 1/5 times 1/5 which is 1/25. Since we’re finding the probability of landing on the ANY color two times in a row, there are five colors, so... (1/25) times 5, which is equal to 1/5
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1.5 meters equal how many cm
hram777 [196]
1 meter = 100 cm. So 1 1/2 meters = 150 cm.
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3 years ago
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I am a three-digit number. My second digit is 4 times bigger than the third digit. My first digit is 3 less than my second digit
labwork [276]

Answer:

285

Step-by-step explanation:

use algebra

third is x

second is 4x

first is 4x-3

x+4x+4x-3

9x-3 = x+x+1+x+2

9x-3=3x+3

12x=6, divide x=2

third is 2, sec is 8, first is 5

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3 years ago
Whats 2+2? please help i literally dont know
UkoKoshka [18]

Answer:

2 + 2 = 4

Step-by-step explanation:

 

8 0
3 years ago
What is the completely factored form of this polynomial?
Sholpan [36]

Answer:

A. (x + 2)²(x - 2)²

Step-by-step explanation:

x⁴ - 8x² + 16 =

(x² - 4)(x² - 4) =

(x - 2)(x + 2)(x - 2)(x + 2) =

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5 0
3 years ago
The rate of transmission in a telegraph cable is observed to be proportional to x2ln(1/x) where x is the ratio of the radius of
sergij07 [2.7K]

Answer:

The value of x that gives the maximum transmission is 1/√e ≅0.607

Step-by-step explanation:

Lets call f the rate function f. Note that f(x) = k * x^2ln(1/x), where k is a positive constant (this is because f is proportional to the other expression). In order to compute the maximum of f in (0,1), we derivate f, using the product rule.

f'(x) = k*((x^2)'*ln(1/x) + x^2*(ln(1/x)')) = k*(2x\,ln(1/x)+x^2*(\frac{1}{1/x}*(-\frac{1}{x^2})))\\= k * (2x \, ln(1/x)-x)

We need to equalize f' to 0

  • k*(2x ln(1/x) - x) = 0 -------- We send k dividing to the other side
  • 2x ln(1/x) - x = 0 -------- Now we take the x and move it to the other side
  • 2x ln(1/x) = x -- Now, we send 2x dividing (note that x>0, so we can divide)
  • ln(1/x) = x/2x = 1/2 -------  we send the natural logarithm as exp
  • 1/x = e^(1/2)
  • x = 1/e^(1/2) = 1/√e ≅ 0.607

Thus, the value of x that gives the maximum transmission is 1/√e.

7 0
3 years ago
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