Part A.
Using the Pythagorean theorem,
PR² = PQ² +QR²
PR² = (14 ft)² +(6 ft)² = 196 ft² +36 ft² . . . . substitute the given numbers
PR² = 232 ft² . . . . . . . . . . . . . . . . . . . . . . . .find the sum
PR = √(232 ft²) ≈ 15.23 ft . . . . . . . . . . . . . take the square root
The length of rod PR is 15.23 ft.
Part B.
Using the Pythagorean theorem,
PR² = PQ² +QR²
(16 ft)² = (14 ft)² +QR² . . . . . . . substitute the given numbers
256 ft² -196 ft² = QR² . . . . . .. subtract 14²
60 ft² = QR² . . . . . . . . . . . . . . find the sum
√(60 ft²) = QR ≈ 7.75 ft . . . . . take the square root
The new height QR is about 7.75 ft.
It should be 120ft^2. you multiple like you would a cube then divide by two
Answer:
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Step-by-step explanation:
Answer:
The y-value is -20
Step-by-step explanation:
So let's solve this by Elimination method;
-2(4x + 5y = -12)
4(2x + 3y = -16)
Let's Distribute;
-8x - 10y = 24
8x + 12y = -64
So x cancels out because -8 + 8 = 0
-10y + 12y = 2y
24 - 64 = -40
2y = -40
Divide both sides by 2;
y = -20
Now lets plug in y to find the value of x;
4x + 5(-20) = -12
4x - 100 = -12
Add 100 to both sides;
4x = 88
Divide both sides by 4;
x = 22
