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lana66690 [7]
3 years ago
6

The sum of a number,n,and 5

Mathematics
2 answers:
grin007 [14]3 years ago
7 0
The question did not ask for the sum of the first counting number five times! The sum of the first 5 counting
Mnenie [13.5K]3 years ago
6 0
Sum is the answer in addition, so add n and 5

n + 5
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12 pens cost £3.00. How many pens can be bought for £8?
igor_vitrenko [27]

Answer:

<u>You can buy 32 pens for £8.</u>

Step-by-step explanation:

12÷3 =  4  ---> which means you get 4 pens for £1.

since you get 4 pens for £1, you need to multiply 4x8 to find how many pens you can buy for £8.

4x8 = 32.

<u>You can buy 32 pens for £8.</u>

<u />

<em>hope this helps !</em>

have an amazing day : )

6 0
3 years ago
Mary stated that 2.01 x 10⁶ is less than 4.8 x 10⁴ because 2.01 is less than 4.8. what was mary's mistake ?
katrin [286]

Answer:

Step-by-step explanation:

Scientific notation is always written as a number between 1 and 9.9999999 repeating. There follows a power of 10. I'm not sure which answer would help you see it clearer but

4.8 * 10^4 the decimal is shifted 4 places the right which is 48000 where you have no numbers, you use zeros.

2.01 * 10^6 means that you shift the decimal 6 places to the right.

2010000

So 2 million is larger than 48 thousand.

The other way to do it is just to look at the power. 6 is more than 4. 6 describes the number of places you move. So does 4. 6>4 so that's the larger number.

4 0
3 years ago
What is 7/4 as a mixed number
valentinak56 [21]
The answer to the question is 1 and 3/4
6 0
3 years ago
Read 2 more answers
Jada solved the equation Negative StartFraction 4 over 9 EndFraction = StartFraction x over 108 EndFraction for x using the step
navik [9.2K]

Answer:

A

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Can someone do #4 and #5
Hitman42 [59]

Answer:

First, find two points on the graph:

  • (x₁, y₁) = (0, 2)
  • (x₂, y₂) = (2, 8)

Slope = \frac{y_{2}-y_{1} }{x_{2}-x_{1}} = \frac{8-2}{2-0} =\frac{6}{2}=3

16 + (-3) = 16 - 3 = 13

8 0
2 years ago
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