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3 years ago

JK has endpoints J(13,8) and K(-6,-6). Find the coordinates of the midpoint JK

2 answers:

8 0

This is accomplished by averaging the x and y coordinates.

So the midpoint's x coordinate is found as (13+-6)/2 = 3.5
Similarly, the y coordinate is (8+-6)/2 = 1

So the point is (3.5,1)

vazorg [7]3 years ago

6 0

Answer:

i took the test so i will give you the right answer.

Step-by-step explanation:

the answer is 3.5,1

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6000 ft

Step-by-step explanation:

Let length of rectangular field=x

Breadth of rectangular field=y

Area of rectangular field= $1500000$ square ft

Area of rectangular field= $l\times b$

Area of rectangular field= $x\time y$

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$y=\frac{1500000}{x}$

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Differentiate w.r.t x

$P'(x)=2-\frac{4500000}{x^2}$

Using formula: $\frac{dx^n}{dx}=nx^{n-1}$

$P'(x)=0$

$2-\frac{4500000}{x^2}=0$

$\frac{4500000}{x^2}=2$

$x^2=\frac{4500000}{2}=2250000$

$x=\sqrt{2250000}=1500$

It is always positive because length is always positive.

Again differentiate w.r.t x

$P''(x)=\frac{9000000}{x^3}$

Substitute x=1500

$P''(1500)=\frac{9000000}{(1500)^3}>0$

Hence, fencing is minimum at x=1 500

Substitute x=1 500

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3 years ago

Find the volume of a right circular cone that has a height of 16.8 in and a base with a

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Answer:

Volume of right circular cone is 388.43 in³

Step-by-step explanation:

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The formula used for calculating volume of a right circular cone is: $Volume=\pi r^2\frac{h}{3}$

Putting values and finding volume

$Volume=\pi r^2\frac{h}{3}\\Volume=3.14\times (4.7)^2 \times \frac{16.8}{3}\\Volume=3.14\times 22.09 \times 5.6\\Volume= 388.43 \:in^3$

So, Volume of right circular cone is 388.43 in³

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2 years ago

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Answer:

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