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makkiz [27]
3 years ago
9

JK has endpoints J(13,8) and K(-6,-6). Find the coordinates of the midpoint JK

Mathematics
2 answers:
Strike441 [17]3 years ago
8 0
This is accomplished by averaging the x and y coordinates.

So the midpoint's x coordinate is found as (13+-6)/2 = 3.5
Similarly, the y coordinate is (8+-6)/2 = 1

So the point is (3.5,1)
vazorg [7]3 years ago
6 0

Answer:

i took the test so i will give you the right answer.

Step-by-step explanation:

the answer is 3.5,1

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If two planes intersect, they intersect in exactly one ?
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Yes.

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A square is divided into nine smaller squares of equal area. The center square is then divided into nine smaller squares of equa
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1/2 of the figure is shared

Step-by-step explanation:

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2 years ago
Which triangle congruency postulate would you use to show ATW = AKW
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SSS

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3 years ago
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How do you Subtract 9x^2 + 22x - 46 from 12x^2 - 8x + 12.
Luba_88 [7]

Subtract the x^2 terms from each other, then the x terms, then the ones without any x whatsoever.

(12x^2 - 8x + 12) - (9x^2 +22x-46)

First, we'll subtract 9x^2 from 12x^2

12x^2-9x^2- = 3x^2

Result: 3x^2

Next, we'll subtract 22x from -8x

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Result: -30x

Finally, we'll subtract -46 from 12

12-(-46) = 12+46 = 58

Result: 58

Now, we can add these 3 results together.

First, we had 3x^2, then -30x, and finally 58.

Thus, our subtraction of

(12x^2 - 8x + 12) - (9x^2 +22x-46)

equals

3x^2-30x+58

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3 years ago
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