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jeka94
3 years ago
14

Solve the system. Estimate the solution first. Enter whole numbers for the estimated solution and improper fractions in simplest

form for the algebraic solution.
6x + y = 4
x − 4y = 19
The estimated solution is (___,___)
The algebraic solution is (___,___)

HELPPP PLZZZ DUEE TODAYYY
Mathematics
1 answer:
Harrizon [31]3 years ago
6 0

Answer:

estimated (1,-4) algebraic (7/5.-22/5)

Step-by-step explanation:

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3x(-2x)8(-2)=30 what value of x makes the equation true.<br><br> A. 24<br> B.26<br> C.5<br> D.6
Leokris [45]

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5 0
3 years ago
Explain how a(b + c) can be rewritten as (b + c)a and as ba + ca.
jenyasd209 [6]

Answer:

#UseDistributiveProperty

Step-by-step explanation:

6 0
3 years ago
At a specific point on a highway, vehicles arrive according to a Poisson process. Vehicles are counted in 12 second intervals, a
morpeh [17]

Answer: a) 4.6798, and b) 19.8%.

Step-by-step explanation:

Since we have given that

P(n) = \dfrac{15}{120}=0.125

As we know the poisson process, we get that

P(n)=\dfrac{(\lambda t)^n\times e^{-\lambda t}}{n!}\\\\P(n=0)=0.125=\dfrac{(\lambda \times 14)^0\times e^{-14\lambda}}{0!}\\\\0.125=e^{-14\lambda}\\\\\ln 0.125=-14\lambda\\\\-2.079=-14\lambda\\\\\lambda=\dfrac{2.079}{14}\\\\0.1485=\lambda

So, for exactly one car would be

P(n=1) is given by

=\dfrac{(0.1485\times 14)^1\times e^{-0.1485\times 14}}{1!}\\\\=0.2599

Hence, our required probability is 0.2599.

a. Approximate the number of these intervals in which exactly one car arrives

Number of these intervals in which exactly one car arrives is given by

0.2599\times 18=4.6798

We will find the traffic flow q such that

P(0)=e^{\frac{-qt}{3600}}\\\\0.125=e^{\frac{-18q}{3600}}\\\\0.125=e^{-0.005q}\\\\\ln 0.125=-0.005q\\\\-2.079=-0.005q\\\\q=\dfrac{-2.079}{-0.005}=415.88\ veh/hr

b. Estimate the percentage of time headways that will be 14 seconds or greater.

so, it becomes,

P(h\geq 14)=e^{\frac{-qt}{3600}}\\\\P(h\geq 14)=e^{\frac{-415.88\times 14}{3600}}\\\\P(h\geq 14)=0.198\\\\P(h\geq 14)=19.8\%

Hence, a) 4.6798, and b) 19.8%.

7 0
3 years ago
Your round-trip drive to work is 4310 4 3 10 miles. How many miles do you drive to and from work in 3 3 days? CLEAR CHECK
luda_lava [24]

Answer:

if the round trip to work is 10 miles (i cant tell how many because it says 4310 4 3 10 miles lol) then you would travel 30 miles in 3 days

8 0
3 years ago
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