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jeka94
3 years ago
14

Solve the system. Estimate the solution first. Enter whole numbers for the estimated solution and improper fractions in simplest

form for the algebraic solution.
6x + y = 4
x − 4y = 19
The estimated solution is (___,___)
The algebraic solution is (___,___)

HELPPP PLZZZ DUEE TODAYYY
Mathematics
1 answer:
Harrizon [31]3 years ago
6 0

Answer:

estimated (1,-4) algebraic (7/5.-22/5)

Step-by-step explanation:

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Solve<br> 13^x+2=5<br> having a bit of trouble
-Dominant- [34]
<em>Solve: </em>13^{x} + 2 = 5

Start by isolating the x-variable as much as you can:
13^{x} = 5 - 2 = 3
13^{x} = 3

Now, if we take the log with base 13 of both sides, then the left hand side will cancel out really easily. This is based on the concept of inverse operations. For example, when we take the square of a square root, we get our initial value. This is because the two operations are inverses of each other, and basically undoes each other.

Logarithms and exponentials are the inverse operations of each other. If we want to extrapolate the power of an exponential, we take the logarithmic function of it, and vice versa.

In this case, we are saying what power of '13' will produce us with 13ˣ, and the only answer will be x itself.

log_{13}(13^{x}) = log_{13}(3)
x = log_{13}(3)
3 0
3 years ago
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barxatty [35]
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3 0
3 years ago
If cos theta is -5/13 and sin θ &lt; 0, what is tan θ ?
tensa zangetsu [6.8K]
Take the right angled triangle  with sides 13, 12 and 5. sine theta will be 12/13

When sin theta < 0 and cos theta < 0  we are in the  third  quadrant  so sin theta will be -12/13

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7 0
3 years ago
Write the equations of the line with the slope=6 that passes through (4,-6)
algol [13]

Answer:

y=6x+18

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Write 169=13^2 in logarithmic form​
e-lub [12.9K]

Answer:

\log_{13}(169)=2

Step-by-step explanation:

The given exponential form is:

169=13^2

The base of the given expression on the right is 13 and the exponent is 2.

The number is 169.

In terms of logarithms, the base still remains the base and the exponent becomes the result of the logarithm of the number 169 to the given base 13.

\log_{13}(169)=2

4 0
3 years ago
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