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3 years ago

WORTH 22 POINTS please help me :)

Mathematics

1 answer:

GarryVolchara [31]3 years ago

8 0

ANSWER

on a it would be 24 because 34 is not right if you add 12+12. B would be 60$ is the cost of five tickets

Step-by-step explanation:

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A pendant is formed using a cylinder and cone. Once assembled, as shown below, the pendant is painted. How many square millimete

solmaris [256]

Surface area of cylinder is given by area of circle + area of the rectangle that curved around the cylinder

Area of the base of the cylinder = $\pi r^{2} = 8^{2} \pi =64 \pi$
Area of the cylinder 'wall' = width × length = $12$ × $2r \pi$ = $12$ × $16 \pi$ = $192 \pi$

Note that the wall of the cylinder is in the shape of a rectangle. The width of the rectangle is the height of the cylinder. The length of the rectangle is the circumference of the circle base.

Surface area of cone is given by $\pirl$ where $l$ is the slanted height of the cone

SA of cone = $\pi (8)(10)=80 \pi$

Hence total painted surface area is $80 \pi +192 \pi +64 \pi =336 \pi$

3 0

3 years ago

Read 2 more answers

If s is an increasing function, and t is a decreasing function, find Cs(X),t(Y ) in terms of CX,Y .

Sedbober [7]

Answer:

C(X,Y)(a,b)=1−C(s(X),t(Y))(a,1−b).

Step-by-step explanation:

Let's introduce the cumulative distribution of (X,Y), X and Y :

F(X,Y)(x,y)=P(X≤x,Y≤y)

FX(x)=P(X≤x)
FY(y)=P(Y≤y).

Likewise for (s(X),t(Y)), s(X) and t(Y) :

F(s(X),t(Y))(u,v)=P(s(X)≤u

t(Y)≤v)
Fs(X)(u)=P(s(X)≤u)
Ft(Y)(v)=P(t(Y)≤v).

Now, First establish the relationship between F(X,Y) and F(s(X),t(Y)) :

F(X,Y)(x,y)=P(X≤x,Y≤y)=P(s(X)≤s(x),t(Y)≥t(y))

The last step is obtained by applying the functions s and t since s preserves order and t reverses it.

This can be further transformed into

F(X,Y)(x,y)=1−P(s(X)≤s(x),t(Y)≤t(y))=1−F(s(X),t(Y))(s(x),t(y))

Since our random variables are continuous, we assume that the difference between t(Y)≤t(y) and t(Y)<t(y)) is just a set of zero measure.

Now, to transform this into a statement about copulas, note that

C(X,Y)(a,b)=F(X,Y)(F−1X(a), F−1Y(b))

Thus, plugging x=F−1X(a) and y=F−1Y(b) into our previous formula,

we get

F(X,Y)(F−1X(a),F−1Y(b))=1−F(s(X),t(Y))(s(F−1X(a)),t(F−1Y(b)))

The left hand side is the copula C(X,Y), the right hand side still needs some work.

Note that

Fs(X)(s(F−1X(a)))=P(s(X)≤s(F−1X(a)))=P(X≤F−1X(a))=FX(F−1X(a))=a

and likewise

Ft(Y)(s(F−1Y(b)))=P(t(Y)≤t(F−1Y(b)))=P(Y≥F−1Y(b))=1−FY(F−1Y(b))=1−b

Combining all results we obtain for the relationship between the copulas

C(X,Y)(a,b)=1−C(s(X),t(Y))(a,1−b).

7 0

3 years ago

A student incorrectly determined that the length of DE is 29 cm explaining that 12-7 = 5 and 36-7 = 29 explain what mistake the

FinnZ [79.3K]

Answer:

The length of the hypotenuse ≈ 39.7 cm

Explanation:

Since the given triangle is a right-angled triangle, this means that we can apply the Pythagorean theorem.

The equation for Pythagorean calculation is:

(hypotenuse)² = (first leg)² + (second leg)²

In the given, we have:

first leg = 30 cm

second leg = 26 cm

Substitute with the givens in the above equation to get the hypotenuse as follows:

(hypotenuse)² = (30)² + (26)²

(hypotenuse)² = 1576

This means that:

either hypotenuse = √1576 = 39.69 ≈ 39.7 cm ..........> accepted

or hypotenuse = -√1576 = -39.69 ......> rejected as length can't be negative

Hope this helps :)

6 0

2 years ago

31 - 2= x+6 <br> Pls help lol

adell [148]

Answer:

31-2=X+6

29=X+6

29-6=X

23=X

6 0

3 years ago

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Evaluate:<br> -9 + 25 - (-10) + (-6)

Minchanka [31]

-9 is a negative number, so plus 25, it would be 16. The minus sign and the negative sign of -10 cancel out, so it is plus 10, ending up with 26. Finally, the + and - becomes negative (positive times negative equals negative), so it is -6 and you’ll end up with a final answer of 20.

4 0

3 years ago

Read 2 more answers