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2 years ago

10

(Which is the simplified form of the expression ? 3(7/5x+4)-2(3/2-5/4x)

1 answer:

Illusion [34]2 years ago

5 0

Answer:

let's see what to do buddy....

Step-by-step explanation:

$3( \frac{7}{5}x + 4) - 2( \frac{3}{2} - \frac{5}{4}x) \\ \\ = \frac{21}{5}x + 12 - 3 + \frac{5}{2}x \\ \\ = \frac{(21 \times 2) + (5 \times 5)}{10} x + 9 = \\ \\ \frac{42 + 25}{10} x + 9 = \frac{67}{10}x + 9 = 6.7x + 9$

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Suppose that the scatterplot shows the response time from websites when computers communicate through the Internet. Paul use the

lukranit [14]

It’s gonna be 300 idk how to explain but it is 300

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3 years ago

Please help me answer this

xxMikexx [17]

The answer would be .42

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3 years ago

You have $5600. The best interest rate you can find is 3%

EleoNora [17]

Answer:

18 years

Step-by-step explanation:

The formula for computing accrued amount A for a principal of P at an interest rate of r(in decimal) compounded n times in a year for t years is given by

$A = P(1 + \frac{r}{n})^{nt}$

Note that r is percentage converted to decimal. So 3% = 3/100 = 0.03

We can rearrange the above equation to:

$\frac{A}{P} = (1 + \frac{r}{n})^{nt}$

Taking logs on both sides

$log(\frac{A}{P}) = log(1 + \frac{r}{n})^{nt}$

This gives

$log(\frac{A}{P}) =nt \times log(1 + \frac{r}{n})\\So,\\nt = \frac{log(\frac{A}{P})}{ log(1 + \frac{r}{n})}$

In this particular problem, n = 4, , A= 9600, P = 5600, r =0.03, so r/n = 0.03/4 = 0.0075

1 + r/n = 1+0.0075 = 1.0075

4t = log(9600/5600)/log(1.0075) = log(1.714) / log(1.0075) = 0.234 /0.00325 = 72

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4 0

1 year ago

A) Find a particular solution to y" + 2y = e^3 + x^3. b) Find the general solution.

Reptile [31]

Answer:

a.P.I= $\frac{e^{3x}}{11}+\frac{1}{2}(x^3-3x)$

b.G.S= $C_1Cos \sqrt2 x+C_2 Sin\sqrt2 x+\frac{1}{11}e^{3x}+\frac{1}{2}(x^3-3x}$

Step-by-step explanation:

We are given that a linear differential equation

$y''+2y=e^{3x}+x^3$

We have to find the particular solution

P.I= $\frac{e^{3x}}{D^2+2}+\frac{x^3}{D^2+2}$

P.I= $\frac{e^{3x}}{3^2+2}+\frac{1}{2} x^3(1+\frac{D^2}{2})^{-2}$

P.I= $\frac{e^{3x}}{11}+\frac{1-2\frac{D^2}{4}+3\frac{D^4}{16}+...}{2}x^3$

P.I= $\frac{e^{3x}}{11}+\frac{x^3-2\frac{\cdot3\cdot 2x}{4}}{2}+0}$ (higher order terms can be neglected

P.I= $\frac{e^{3x}}{11}+\frac{1}{2}(x^3-3x)$

b.Characteristics equation

$D^2+2=0$

$D=\pm\sqrt2 i$

C.F= $C_1cos \sqrt2x+C_2 sin\sqrt2 x$

G.S=C.F+P.I

G.S= $C_1Cos \sqrt2 x+C_2 Sin\sqrt2 x+\frac{1}{11}e^{3x}+\frac{1}{2}(x^3-3x)$

3 0

3 years ago

Review the scenario and the solution. Explain what is wrong with solution and correct the error.

butalik [34]

2.25h(60m/hr)(1/3)=45m

So Rick spends 45 minutes studying math per night.

7 0

2 years ago

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