What is the nth term of 4, 6, 8, 10, 12

1 answer:

8 0

$T_n = a_1 + (n - 1)d$

$a_1 = 4 , d = 2$

$T_n = 4 + 2(n - 1)$

$T_n = 4 + 2n - 2$

$T_n = 2n + 2$

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Answer: 2n + 2
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