Look into my attachment
in rhombus ABCD, ∠AOB = 90°
Look at ΔAOBthe sum of inner angles = 180°
∠BAO + ∠AOB + ∠ABO = 180°
2x + 1 + 90 + 2x + 5 = 180°
4x + 96 = 180
4x = 84
x = 21
Answer:
to get coordinate of mid point use (20+0)/2 for x coordinate,
A is correct answer!
we can alsoways find the slope by simply using two points off the table, bearing in mind that slope goes by different names
rate of change
average rate of change
delta difference
rise over run
however is the same cat disguised in different costumes.
![\bf \begin{array}{|cc|ll} \cline{1-2} time&distance\\ \cline{1-2} 15&2\\ 30&4\\ 45&5\\ 60&6\\ \cline{1-2} \end{array} \begin{array}{llll} \\[1em] \leftarrow \\\\ \leftarrow \end{array}\qquad \qquad (\stackrel{x_1}{30}~,~\stackrel{y_1}{4})\qquad (\stackrel{x_2}{60}~,~\stackrel{y_2}{6})](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7B%7Ccc%7Cll%7D%20%5Ccline%7B1-2%7D%20time%26distance%5C%5C%20%5Ccline%7B1-2%7D%2015%262%5C%5C%2030%264%5C%5C%2045%265%5C%5C%2060%266%5C%5C%20%5Ccline%7B1-2%7D%20%5Cend%7Barray%7D%20%5Cbegin%7Barray%7D%7Bllll%7D%20%5C%5C%5B1em%5D%20%5Cleftarrow%20%5C%5C%5C%5C%20%5Cleftarrow%20%5Cend%7Barray%7D%5Cqquad%20%5Cqquad%20%28%5Cstackrel%7Bx_1%7D%7B30%7D~%2C~%5Cstackrel%7By_1%7D%7B4%7D%29%5Cqquad%20%28%5Cstackrel%7Bx_2%7D%7B60%7D~%2C~%5Cstackrel%7By_2%7D%7B6%7D%29)

Answer:
19
Step-by-step explanation:
because you inverse the operation
5 ×3 = 15
15 + 4 = 19