<span><span>(<span><span><span><span>10<span>x5</span></span><span>y12</span></span><span>−5</span></span><span>x<span>−2</span></span></span>)</span><span>(<span>y6</span>)</span></span><span>=<span><span>−<span><span>2<span>x5</span></span><span>y18</span></span></span><span>x2</span></span></span><span>=<span>−<span><span>2<span>x3</span></span><span>y<span>18</span></span></span></span></span>
Answer: 0.9414
Step-by-step explanation:
Given : One of the questions on a survey asked adults if they used the internet at least occasionally.
450 out of 478 adults aged 18–29 answered Yes.
Then, the point estimate of the proportion of adults aged 18–29 who use the internet will be :-

Thus , a point estimate of the proportion of adults aged 18–29 who use the internet= 0.9414
The situation above described that Jeff added two - thirds of 128 to the
flour. The numerical value of (2/3)(128) is 85.33 grams. The recipe
says to add only 32 grams of vanilla flour.
Hence, Jeff went over the
prescribed amount.
To determine the excess amount, subtract 32 from 85.33 which has a numerical value of 53.33 grams.
The correct answer in B) 44.
Step by step answer:
Divide 3 by 90 and you will get 30, meaning that Machine J packed 30 candies per minute. Machine K packed 26 candies per minute as it stated. In order to figure out how many more candies Machine J packed then Machine K in 11 minutes, you would need to figure out how many more candies it packed in one minute then multiply by 11. In this case Machine J packed four more then Machine K in one minute, therefore Machine J packed 44 more than Machine K in 11 minutes.
Hope this helped!