Answer:
![(a)\ f^{-1}(-15) = -6](https://tex.z-dn.net/?f=%28a%29%5C%20f%5E%7B-1%7D%28-15%29%20%3D%20-6)
![(b)\ f^{-1}(4) + f(9)=0](https://tex.z-dn.net/?f=%28b%29%5C%20f%5E%7B-1%7D%284%29%20%2B%20f%289%29%3D0)
Step-by-step explanation:
Given
The attached table
![(a)\ f^{-1}(-15)](https://tex.z-dn.net/?f=%28a%29%5C%20f%5E%7B-1%7D%28-15%29)
This represents an inverse function.
So, we look into x row for its value.
i.e.
![f^{-1}(-15) = -6](https://tex.z-dn.net/?f=f%5E%7B-1%7D%28-15%29%20%3D%20-6)
![(b)\ f^{-1}(4) + f(9)](https://tex.z-dn.net/?f=%28b%29%5C%20f%5E%7B-1%7D%284%29%20%2B%20f%289%29)
Just like (a)
---- by looking into the x rows
![f(9) = 11](https://tex.z-dn.net/?f=f%289%29%20%3D%2011)
So:
![f^{-1}(4) + f(9)=-11 + 11](https://tex.z-dn.net/?f=f%5E%7B-1%7D%284%29%20%2B%20f%289%29%3D-11%20%2B%2011)
![f^{-1}(4) + f(9)=0](https://tex.z-dn.net/?f=f%5E%7B-1%7D%284%29%20%2B%20f%289%29%3D0)
For this, we need to find the lowest common multiple of 12 and 15....
common multiples of 12 : 12,24,36,48,60
common multiples of 15 : 15,30,45,60
LCM = 60
the caller that will be the first to win both is the 60th caller
5x = -2x
5x + 2x = 0
7x = 0
x = 0
43 6 goes into 25 4 times equaling 24 put the 1 carry down thw 8 6 time 3 is 18 that's 43
To find g(f(4)), work from the inside out.
f(4) is 4^2+3, or 16+3, or 19. Now, we must find g(19).
This is 19+5/19. This is already a mixed number, though if you want an improper fraction solution, we have:
361/19+5/19
Which simplifies to:
366/19
Therefore, 366/19 is the answer.